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zzz [600]
3 years ago
7

How do i identify the pairs of congruent angles in figures?

Mathematics
1 answer:
Igoryamba3 years ago
5 0
3) angle MSN and PSQ
4) FGH and WXZ
5) GML and HMJ
3) they are Both equal angles
4) they brother equal 90°
5) they are vertical angles and verticals angles are always congruent
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Fifteen tickets cost $193.75. What is the average cost of each ticket?
julsineya [31]

Answer:

about $12.92

Step-by-step explanation:

could be wrong though

8 0
3 years ago
Read 2 more answers
Your office parking lot has a probability of being occupied of 1/3. You happen to find it unoccupied for nine consecutive days.
olasank [31]

Answer:

0.4

Step-by-step explanation:

Let X be the random variable that represents the number of consecutive days in which the parking lot is occupied before it is unoccupied. Then the variable X is a geometric random variable with probability of success p = 2/3, with probability function f (x) = [(2/3)^x] (1/3)

Then the probability of finding him unoccupied after the nine days he has been found unoccupied is:

P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9). For a geometric aeatory variable:

P (X> = 10) = 1 - P (X <10) = 0.00002

P (X> = 9) = 1 - P (X <9) = 0.00005

Thus, P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9) = 0.00002 / 0.00005 = 0.4.

6 0
3 years ago
Minimize Q=x^2+2y^2, where x+y=3
Studentka2010 [4]
<span>The first step you need to do is to rewrite
x+y=3
as y=3-x
</span><span>Now we can replace the y in the equation with our newfound value for y, which is
y=3-x.
So lets write it now like this
Q=x^2+2(3-y)^2
=x^2+18-12x+2x^2
=3x^2+18-12x
</span>Hope this helps
6 0
3 years ago
The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?
Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                           N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know:

  • The initial quantity of silicone-32 is 30 g.
  • The time elapsed is 300 years.
  • The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g

22.38 g of silicone-32 will be present in 300 years.

7 0
3 years ago
Y = (x + 4)2 - 1<br> Standard form
denpristay [2]

answer :

y = 2x + 7

i hope it helped

3 0
3 years ago
Read 2 more answers
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