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2 years ago

Help, brainiest, five stars, and thanks for correct answers.

Mathematics

1 answer:

Alisiya [41]2 years ago

5 0

Answer: help this werd account just asked me on a date and i dont even know them thay swared and i did not understand do you know what to do i know this is not an aser but pleas help......

Step-by-step explanation: please.........

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Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at

Oksanka [162]

a) The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively.

b) The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

$P'(x,y) = k\cdot P(x,y)$ (1)

Where:

$P(x,y)$ - Original point
$P'(x,y)$ - Dilated point.

If we know that $k = \frac{1}{3}$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ , then the new points of the quadrilateral are:

$A'(x,y) = \frac{1}{3}\cdot (0,6)$

$A'(x,y) = (0, 2)$

$B'(x,y) = \frac{1}{3} \cdot (-3,-6)$

$B'(x,y) = (-1, -2)$

$C'(x,y) = \frac{1}{3}\cdot (-9,-6)$

$C'(x,y) = \left(-3,-2\right)$

$D'(x,y) = \frac{1}{3}\cdot (-12,-3)$

$D'(x,y) = (-4, -1)$

The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively. $\blacksquare$

b) A translation along a vector is defined by following operation:

$P'(x,y) = P(x,y) +T(x,y)$ (2)

Where $T(x,y)$ is the transformation vector.

If we know that $T(x,y) = (-5,-1)$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ ,

$A'(x,y) = (0,6) + (-5, -1)$

$A'(x,y) = (-5, 5)$

$B'(x,y) = (-3, -6) + (-5, -1)$

$B'(x,y) = (-8,-7)$

$C'(x,y) = (-9, -6) + (-5, -1)$

$C'(x,y) = (-13, -7)$

$D'(x,y) = (-12,-3)+(-5,-1)$

$D'(x,y) = (-17, -4)$

The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively. $\blacksquare$

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

7 0

2 years ago

I need help someone ....

kvasek [131]

Answer:

162 ft^2

Step-by-step explanation:

18 * 18 = 324

324/2 = 162

The area of the patio is 162 square feet

7 0

2 years ago

Read 2 more answers

A deep freezer has a temperature of -6°C when it is turned off.

Xelga [282]

Answer:

y = -6 + 1.2*x is the answer I would use, but see the note below.

Step-by-step explanation:

Let x = the number of minutes.

Let y = the temperature at any given time.

y = -6 + 1.2*x

This is the equation that you would use if you were calculating y with a calculator. If you are in a chemistry class it should be written as

y = - 6°C + 1.2°x/ min

4 0

1 year ago

Samantha has a shelf that is 95 over 4 inches wide. How many books can Samantha arrange on the shelf if each book is 5 over 4 in

love history [14]

Answer:

Option 1 - 19, because the number of books is 95 over 4 divided by 5 over 4

Step-by-step explanation:

Given : Samantha has a shelf that is 95 over 4 inches wide.

To find : How many books can Samantha arrange on the shelf if each book is 5 over 4 inches thick?

Solution :

The thickness of shelf = $\frac{95}{4}$ inches

Each book thickness = $\frac{5}{4}$ inches

Let the total number of books that could be arranged in the shelf be 'n'.

$\text{Number\ of\ books\ arranged}=\dfrac{\text{Thickness\ of\ shelf}}{\text{Thickness\ of\ one\ book}}$

Substitute the values,

$n=\dfrac{\dfrac{95}{4}}{\dfrac{5}{4}}$

$n=\dfrac{95\times 4}{5\times 4}$

$n=\dfrac{95}{5}$

$n=19$

Therefore, option 1 is correct.

19, because the number of books is 95 over 4 divided by 5 over 4

4 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> What is [100(−4)^n-1} equal to?

nikklg [1K]

Answer: -5100

<u>Step-by-step explanation:</u>

$\sum^4_1[100(-4)^{n-1}]\qquad \rightarrow \qquad a_1=100\ \text{and r = -4}\\\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\\\\\S_4=\dfrac{100(1-(-4)^4)}{1-(-4)}\\\\\\.\quad=\dfrac{100(1-256)}{1+4}\\\\\\.\quad=\dfrac{100(-255)}{5}\\\\.\quad=20(-255)\\\\.\quad=-5100\\$

3 0

2 years ago