What is 8y=23+3x divided by 8?

1 answer:

6 0

8y = 23 + 3x divided by 8: divide ALL numbers by 8
8y/8 is y
23/8 is 23/8
3x/8 is 3/8x
Therefore, the answer would be;
y = 23/8 + 3/8x, which is the same as y = 3/8x + 23/8

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Suppose a simple random sample of size nequals=6464 is obtained from a population with mu equals 84μ=84 and sigma equals 16σ=16.

Assoli18 [71]

Answer:

a. $\bar X$ is distributed $N(84;4)$

b. $P(\bar X \geq 87.6) = 0.03593$

c. $P(\bar X \leq 79.2) = 0.00820$

d. $P(\79.2 \leq \bar X \leq 87.6) = 0.95587$

Step-by-step explanation:

The central limit theorem states that, for large n, the sampling distribution of the sample mean is approximately normal with mean $\µ$ and variance $\frac{\sigma^2}{n}$ , then, the sample mean is distributed as a normal random variable with means $\mu_{\bar X}=\mu=84$ and variance $\sigma^2_{\bar X}=\frac{\sigma^2}{n}=\frac{16^2}{64}=4$ .