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3 years ago

15

What is the x to y ratio 14x=25y fractions as answers

1 answer:

elixir [45]3 years ago

5 0

14x=25y; /14y
14x/14y=25y/14y
x/y=25/14
x to y ratio is 25/14

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Ok so can someone pls help me on this. It’s math, and pls explain.

Anika [276]

F.v*king ki11 yourself, you gay piece of $.h1t. Gay b17ches like you burn in hell

3 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

Expanding/Factoring

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

<u>Step 2: Differentiate</u>

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

A __________ contains all the subset of superset. A superset. B proper subset. C null set 2.Positive square root of 1/3 is______

aivan3 [116]

Answer:

i) superset (A)

ii) 0.577 (A)

Step-by-step explanation:

i) A subset is a set which has all its elements contained in another set.

For two sets A and B, if each element of set A is an element of set B, then A is a subset of B.

A superset is a set that houses another set. So if set A is a subset of set B, then B is a superset of A.

Proper subset

For a set (A) to be a proper subset of another (B) every element of A would be in B but there exists at least one element in B that is not in A.

An Empty Set (or Null Set) doesn't have aren't any elements in it. It is empty.

Since every element of the superset is in the superset. Therefore, A superset contains all the subset of superset.

ii) Square root of 1/3 = √⅓

= ± √⅓ = +√⅓ or -√⅓

+√⅓ = +(√1/√3) = +(1/√3)

+√⅓ = +(1/1.7321)

+√⅓ = +0.577

Therefore Positive square root of 1/3 is 0.577 (A)

3 0

3 years ago

I need help with this please hurry it's timed

rodikova [14]

Answer:

I think B 82.3%

Step-by-step explanation:

4 0

2 years ago

In the picture down below

Setler [38]

Answer:

The answer is option A.

The first graph

Hope this helps you

4 0

3 years ago

Read 2 more answers