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Thepotemich [5.8K]
3 years ago
11

Math Post Q3 What inequality describes the graph?

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
7 0

<u>Answer:</u>

A. y\geq \frac{3}{2} x-3

<u>Step-by-step explanation:</u>

We are given a graph and we are to determine which inequality is described by the graph.

Since the graph has a solid line that means that the inequality includes the points on the line and must contain an equal sign.

So we will substitute the point (0, 0) to find the correct inequality.

y\geq \frac{3}{2} x-3

0\geq \frac{3}{2} (0)-3

0\geq 3 - true

y\leq \frac{3}{2} x-3

0\leq \frac{3}{2} (0)-3

0\leq 3 - false

Therefore, the correct inequality is y\geq \frac{3}{2} x-3.

Eduardwww [97]3 years ago
5 0

For this case it is observed that the border of the region is not dotted, then the inequality includes an equal.

Thus, we discard options C and D.

We substitute the point (0,0) and see if it is fulfilled:

y\geq\frac {3} {2} x-3\\0 \geq\frac {3} {2} (0) -3\\0 \geq0-3\\0 \geq-3

It is fulfilled, so the correct option is A.

Answer:

Option A

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Solve the inequality<br> 3 + 9x &gt;4(x+7)<br> pls help
alexandr402 [8]

Answer:

x<5

Step-by-step explanation:

the greater sign will firstly be changed to = for better solving so we obtain

3+9x=4(x+7)by opening bracket

3+9x=4x+28

9x-4x=28-3

5x=25

divide all through by 5x

we obtain

x=5

the greater sign change here

which is x<5

8 0
2 years ago
What is 7=5x+8 in y=me+b form
tatiyna
I have no idea, do you mean y=mx+n cause if so it's already in that form instead that fact that the 7 is supposed to be a y
5 0
3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
Jamie is buying 5 concert tickets, and he wants his total cost to be no more than $4 Above or below $80. Which inequality models
kumpel [21]

Answer:

Option C \left|80-5x\right|\le 4

Step-by-step explanation:

Let

x ----> the cost of the concert ticket

we know that

The total cost to be no more than $4 Above  $80

so

5x\leq 80+4

Solve for x

x\leq \$16.80

The total cost to be no more than $4  below $80

so

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2

therefore

The inequality that represent this problem is

\left|5x-80\right|\le 4

<u><em>Verify</em></u>

<em>First solution (positive case</em>)

+(5x-80)\le 4

5x\le 80+4

Solve for x

x\leq \$16.80 ----> is ok

<em>Second solution (negative case)</em>

-(5x-80)\le 4

Multiply by -1 both sides

(5x-80)\ge -4

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2 ---> is ok

Remember that

\left|5x-80\right|\le 4 is equivalent to \left|80-5x\right|\le 4

Because is a absolute value

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KATRIN_1 [288]

Answer:

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