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Trava [24]
2 years ago
12

if the parent function is square root of x, describe the translation of this function square root x+7

Mathematics
1 answer:
kotykmax [81]2 years ago
8 0

The function y=\sqrt{x} sits with its starting point at the origin. The function y=\sqrt{(x-h)}+k is translated h units to the left or right and k units up or down. Since our radicand, the value under the square root sign, is x+7, putting that into our standard form it would be x-(-7) because minus a negative is a positive. So we move the parent graph to the left (-7 moves to the left) 7 units. There is no number k so our function is not moving up or down. Only to the left 7.

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9th grade math please help its urgenttt
vovangra [49]

Answer:

B

Step-by-step explanation:

observe

2x^2-5x+5=0\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\=\frac{5\pm \sqrt{(-5)^2-4(2)(5)}}{2(2)}\\=\frac{5\pm \sqrt{-15}}{4}\\=\frac{5\pm i\sqrt{15}}{4}

3 0
3 years ago
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Two functions are shown in the table below: Function 1 2 3 4 5 6 f(x) = −x2 + 4x + 12 g(x) = x + 2 Complete the table on your ow
zubka84 [21]

Answer:

x   f(x)   g(x)

1    15    3

2    16   4

3    15    5

4    12    6

5    7     7

6    0     8

f(x) = g(x) when x = 5

Step-by-step explanation:

f(x) = -x² + 4x + 12

f(1) = -(1)² + 4(1) + 12 = 15

f(2) = -(2)² + 4(2) + 12 = 16

f(3) = -(3)² + 4(3) + 12 = 15

f(4) = -(4)² + 4(4) + 12 = 12

f(5) = -(5)² + 4(5) + 12 = 7

f(6) = -(6)² + 4(6) + 12 = 0

g(x) = x + 2

g(1) = 1 + 2 = 3

g(2) = 2 + 2 = 4

g(3) = 3 + 2 = 5

g(4) = 4 + 2 = 6

g(5) = 5 + 2 = 7

g(6) = 6 + 2 = 8

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3 years ago
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Answer:

Only D,F, and G are perfect cubes.

Step-by-step explanation:

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B) Not a perfect cube

C) Not a perfect cube

D) Yes. 3*3=9

E) Not a perfect cube

F) Yes. 8*8=64

G) Yes. 10*10=100

H) Not a perfect cube

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The answer should be d
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cancel the pi
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