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Trava [24]
3 years ago
12

if the parent function is square root of x, describe the translation of this function square root x+7

Mathematics
1 answer:
kotykmax [81]3 years ago
8 0

The function y=\sqrt{x} sits with its starting point at the origin. The function y=\sqrt{(x-h)}+k is translated h units to the left or right and k units up or down. Since our radicand, the value under the square root sign, is x+7, putting that into our standard form it would be x-(-7) because minus a negative is a positive. So we move the parent graph to the left (-7 moves to the left) 7 units. There is no number k so our function is not moving up or down. Only to the left 7.

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Amir stands on a balcony and throws a ball to his dog, who is at ground level.
Mariana [72]

Answer:

3 seconds

Step-by-step explanation:

To find the highest point, we want to find the vertex of the parabola.  Since the function will be negative, the vertex will represent the highest point.  

To find the vertex we want this equation in vertex form:

y=a(x−h)2+k

and the vertex will be (h,k)

We can expand the equation h(x)=-(x+1)(x-7) to be:

h(x) = -x^{2} +6x+7

To get the vertex form we need to complete the square.

The vertex form is :

-(x-3)^{2} +16

so our vertex is (3,16)

This means the highest point will be 16 when x = 3

6 0
3 years ago
Read 2 more answers
Indefinite integral need help pleaseeeeeee
tatiyna
Integrate indefinite integral:
I=\int\frac{dx}{e^{2x}+3e^x+2}dx

Solution:
1. use substitution u=e^x 
=>
du=e^xdx
=>
dx=\frac{du}{e^x}
=>
dx=\frac{du}{u}
=>
I=\int\frac{du}{u(u^2+3u+2)}du
=\int\frac{du}{u(u+2)(u+1)}du
2. decompose into partial fractions
\frac{1}{u(u+2)(u+1)}
=\frac{A}{u}+\frac{B}{u+2}+\frac{C}{u+1}
where A=1/2, B=1/2, C=-1
=\frac{1}{2u}+\frac{1}{2(u+2)}-\frac{1}{u+1}
3. Substitute partial fractions and continue
I=\int\frac{du}{2u}+\int\frac{du}{2(u+2)}-\int\frac{du}{u+1}
=\frac{log(u)}{2}+\frac{log(u+2)}{2}-log(u+1)}
4. back-substitute u=e^x
=\frac{log(e^x)}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}
=\frac{x}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}

Note: log(x) stands for natural log, and NOT log10(x)

7 0
3 years ago
73 POINTS ANSWER QUICKLY AND CORRECTLY, WILL GIVE BRAINLIEST
balu736 [363]

Answer:

y = -2x+4

Step-by-step explanation:

slope = (y2-y1)/(x2-x1)

   = (-4-2)/(4-1)

     = -6/3

  = -2

point slope form

y-y1 = m(x-x1)

y-2 = -2(x-1)

distribute

y-2 =-2x +2

add 2 to each side

y-2 +2 =-2x+2+2

y = -2x+4

in slope intercept form

y = -2x+4

5 0
3 years ago
At a point on the ground 50 feet from the foot of a tree, the angle of elevation to the top of the tree is
disa [49]

Answer:

At a point on the ground 50 feet from the foot of a tree, the angle of elevation to the top of the tree is 53°. Find the height of the tree to the nearest foot.

I got 50xtan53 = 66.35 nearest foot ? would I use tan or sin since I'm finding the foot of the tree

Step-by-step explanation:

.

3 0
3 years ago
colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
kaheart [24]
To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
k_{2} = ln(2)/3 = 0.23105 per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
A_{f1} = 204,800

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

3 0
3 years ago
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