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Bad White [126]
3 years ago
13

A tilted bed is said to have a _____, describing the angle that the bed forms with the horizontal plane--and a _____,the compass

direction that lies at right angles to the tilted bed.
Physics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

The answer to the question is

A tilted bed is said to have a _dip____, describing the angle that the bed forms with the horizontal plane--and a strike, the compass direction that lies at right angles to the tilted bed.

Explanation:

The dip of a tilted bed, describes the acute angle a tilted bed makes with the horizontal plane, by stating the numerical value of the angle from 0 to 90 degrees  as well as pointing out the orientation of the downward dipping direction in the orientation towards N, S, E, W

The strike line represents the line formed to represent the intersection of a feature of a bed  such as the bed rock surface with a horizontal plane.

The dip and the strike line of a tilted bed are always at right angles to each other on a geologic map.

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A bowling ball with a circumference of 27 in. weighs 14.8 lb and has a radius of gyration of 3.43 in. If the ball is released wi
Marrrta [24]

Answer:

Distance covered is 37.63 ft

Solution:

As per the question:

Circumference of the bowling ball, C = 27 in

Weight of the bowling ball, w = 14.8 lb

Radius of gyration, k = 3.43 in

Velocity of release of the ball, v' = 23 ft/s = 276 in/s

Coefficient of friction, \mu = 0.19

Now,

We know that the circumference of the circle is given by:

C = 2\pi R

27 = 2\pi R

R = \frac{27}{2\pi } = 4.29\ in

Also, in case of rolling, we know that:

Angular velocity, \omega = \frac{v}{R}

v = \omega R

Now, applying the conservation of angular momentum along the floor:

Initial angular momentum = Final angular momentum

m\omega' = m\omega + I\omega

Moment of Inertia, I = \frac{2}{5}mR^{2} = mk^{2}

mv'R = mvR + mk^{2}\times \frac{v}{R}

v'R = vR + k^{2}\times \frac{v}{R}

276\times 4.29 = 4.29v + 3.43^{2}\times \frac{276}{4.29}

1184.04 - 756.903 = 4.29v

v = 99.56 in/s

Now,

Friction force, f = \mu mg

Also, acceleration of the ball can be computed as:

\mu mg = - ma

a = - \mu g = - 0.19\times 386.09 = - 73.357\ in/s^{2}

Now, the distance, d covered by the ball before rolling without slipping:

v^{2} = v'^{2} + 2ad

99.56^{2} = 276^{2} + 2\times (- 73.357)d

99.56^{2} - 276^{2} = 2\times (- 73.357)d

d = 451.65 in = 37.53 ft

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vredina [299]

Explanation:

It is given that,

Density of asteroid, \rho=4000\ kg/m^3

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We need to find the diameter of the asteroid. The formula of density is given by:

\rho=\dfrac{m}{V}

V is the volume of spherical shaped asteroid, V=\dfrac{4}{3}\pi r^3

r^3=\dfrac{3M}{4\pi \rho}

r^3=\dfrac{3\times 10^{17}\ kg}{4\pi \times 4000\ kg/m^3}

r^3=\sqrt{5.96\times 10^{12}}

r = 2441311.12 m

Diameter = 2 × radius

d = 4882622.24 m

or

d=4.88\times 10^6\ m

Hence, this is the required solution.

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Answer:

Explanation:

It is determined by the amount of cold or hot water in the mixture to know if it will be closer to been hot or cold.

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Answer:

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Nikolay [14]

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