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3 years ago

Force is a vector because it has both magnitude and

Physics

2 answers:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

direction

Explanation:

il63 [147K]3 years ago

6 0

Answer:

and direction

Explanation:

because when we definite force force is the pull or push of an object and when a force is exerted on the object it works 3 tasks 1, it multiply the force , 2, it multiply the speed, 3, it changes the directions so when we see a vector quantity is a quantity that have both magnitude and direction so when it multiply it's force and speed the object will have magnitude and when it multiply it's direction the object will have a direction. thank you for reading this explanation.☺☺☺☺

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What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperatu

Firlakuza [10]

Answer: 9.0 atm

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=3.0atm\\V_1=150mL\\P_2=?mmHg\\V_2=50mL$

Putting values in above equation, we get:

$3.0\times 150mL=P_2\times 50mL\\\\P_2=9.0atm$

Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm

5 0

4 years ago

List the types of radiation in the electromagnetic spectrum from lowest to highest

Ahat [919]

Radio waves, Television waves, Microwaves, Infrared light, Visible light, Ultraviolet rays, X - rays, Gamma rays, and i think thats about it.

Sorry if i get this wrong Im in elementry school
Hope this helped :)

8 0

4 years ago

Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m . Sim

Nonamiya [84]

Answer:

The distance covered by puck A before collision is $z = 8.56 \ m$

Explanation:

From the question we are told that

The label on the two hockey pucks is A and B

The distance between the two hockey pucks is D 18.0 m

The speed of puck A is $v_A = 3.90 \ m/s$

The speed of puck B is $v_B = 4.30 \ m/s$

The distance covered by puck A is mathematically represented as

$z = v_A * t$

=> $t = \frac{z}{v_A}$

The distance covered by puck B is mathematically represented as

$18 - z = v_B * t$

=> $t = \frac{18 - z}{v_B}$

Since the time take before collision is the same

$\frac{18 - z}{V_B} = \frac{z}{v_A}$

substituting values

$\frac{18 -z }{4.3} = \frac{z}{3.90}$

=> $70.2 - 3.90 z = 4.3 z$

=> $z = 8.56 \ m$

8 0

3 years ago

In a collision between two objects having unequal masses, how does magnitude of the impulse imparted to the lighter object by th

olasank [31]

<span>Both objects receive the same impulse.</span>

3 0

3 years ago

A 2.4 kg box has an initial velocity of 3.6 m/s upward along a plane inclined at 27◦ to the horizontal. The coefficient of kinet

Vika [28.1K]

Answer:

d= 1.18 m

Explanation:

In abscense of friction, total mechanical energy must be constant, i.e.,

ΔK + ΔU = 0

As we are told that there exists a kinetic friction between the box and the plane, we need to take into account the work done by the friction force in the equation, as follows:

ΔK + ΔU = Wnc (1)

If we take as our zero gravitational potential energy reference, the height at which the box is sent upward, we can write the following equations for the different terms in (1):

ΔK = Kf- K₀ = 0 - 1/2*m*v₀² = -1/2*2.4kg* (3.6)²(m/s)² = -15.6 J

ΔU = Uf - U₀ = m*g*h = *m*g*d*sin θ = 2.4 kg*9.81 m/s²*d*0.454 = 10.7*d J

Wnc = Ff. d* cos (180º) = μk*N*d*cos(180º) (2)

The friction force always opposes to the displacement, so the angle between force and displacement is 180º.

The normal force, as is always perpendicular to the surface, takes the value needed to equilibrate the component of the weight perpendicular to the incline, as follows:

N = m*g*cosθ = 2.4 kg*9.81 m/s²*cos 27º = 21 N

Replacing in (2):

Wnc = 0.12*21*cos (180º) = -2.52*d J

Replacing in (1):

-15.6 J + 10.7*d J = -2.52*d J

Solving for d:

d = 1.18 m

7 0

3 years ago