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sweet [91]
3 years ago
9

Force is a vector because it has both magnitude and

Physics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

direction

Explanation:

<3

il63 [147K]3 years ago
6 0

Answer:

and direction

Explanation:

because when we definite force force is the pull or push of an object and when a force is exerted on the object it works 3 tasks 1, it multiply the force , 2, it multiply the speed, 3, it changes the directions so when we see a vector quantity is a quantity that have both magnitude and direction so when it multiply it's force and speed the object will have magnitude and when it multiply it's direction the object will have a direction. thank you for reading this explanation.☺☺☺☺

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Find the west component of 45 m 19º S of W
BaLLatris [955]

Answer:

The west component of the given vector is - 42.548 meters.

Explanation:

We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:

(x, y) = (r_{x}, r_{y})

Where:

r_{x} - Horizontal component of vector distance, measured in meters.

r_{y} - Vertical component of vector distance, measured in meters.

Let suppose that east and north have positive signs, then we get the following expression:

(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]

(x, y) = (-42.548,-14.651)\,[m]

The west component corresponds to the first component of the ordered pair. That is to say:

x = -42.548\,m

The west component of the given vector is - 42.548 meters.

8 0
4 years ago
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Vitek1552 [10]
Deceleration = 29250 / 6500 = 4.5 m/s^2
7 0
4 years ago
Formula for working maximum velocity? ​
Varvara68 [4.7K]

Answer:

v=Aω.

Explanation:

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8 0
3 years ago
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A rocket accelerates upward from rest at a rate of 5 m/s^2. At a height of 1000m, the engines burn out and it coasts the rest of
laila [671]

Answer:

Explanation:

Given

acceleration of rocket(a)=5 m/s^2

At h=1000 m rocket burn out

v^2-u^2=2as

v^2-0=2\times 5\times 1000

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(b) time to reach v=100 m/s

v=u+at

100=0+5\times t

t=\frac{100}{5}=20 s

(c)Rocket maximum altitude

v^2-u^2=2as

here u=100 m/s

v=0

a=9.8 m/s^2

s=\frac{v^2}{2g}

s=\frac{100^2}{2\times 9.8}

[tex]s=510.204

Therefore maximum altitude=510.204+1000=1510.204 m

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3 years ago
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