The pressure exerted on the table due to the book is 200 N/m².
The given parameters;
- <em>mass of the book, m = 400 g = 0.4 kg</em>
- <em>dimension of the table, = 0.10m x 0.20 m.</em>
- <em>gravitational field strength g = 10 N/kg.</em>
The area of the table is calculated as follows;
A = 0.1 x 0.2 = 0.02 m²
The pressure exerted on the table due to the book is calculated as follows;
where;
- <em>F is the force of the book due to its weight</em>
<em />
Thus, the pressure exerted on the table due to the book is 200 N/m².
Learn more here:brainly.com/question/21935783
Using Ohm's Law:
V = IR
Where V = Voltage in Volts, I = Current in Ampere, R = Resistance in Ohms
V = IR
1.5 = I * 3
1.5 = 3I
3*I = 1.5
I = 1.5/3
I = 0.50 A
Current in the Circuit is 0.50 Ampere.
Answer:
4 : 1
Explanation:
<h3><u>Pulse rate</u></h3>
Also referred as heart rate can be affected due to vigorous exercise, age, health. Normally the pulse rate of an adult is between 60 to 100 beats per minute. pulse rate: 80 bpm.
<h3><u>Breathing rate</u></h3>
The amount of oxygen taken in inside of our body from the air. Breathing rate is usually affected due to age. Normal breathing rate of an adult is between 15 to 24 breaths per minute. breathing rate: 20 bpm.
<h3><u>Ratio of breathing to pulse rate</u></h3>
pulse rate : breathing rate
80 : 20
4 : 1
<span>Applied Force Direction vector = [0,1,3]
force F = j + 4k
torque is t = 100 Newton-meters = r x F
Wrench is 0.5 meters long on positive side of the y-axis, r = 0.6 = [0,0.6,0]
We know torque |t| = |r x F| = |r| x |F| sin theta
r x F = |r| x |F| cos theta
r x (j + 3k) = |r| x |j + 3k| cos theta
=> [0,0.6,0] [0,1,3] = 0.6 x squareroot of ((0)^2 + (1)^2 + (3)^2) cos theta
=> 0.6 = 0.6 x squareroot of (1 + 9) cos theta
=> cos theta = 1 / squareroot of (10)
Calculationg the sin theta,
sin theta = squareroot of (1 - (1 / squareroot of (10))^2) = squareroot of (9/10)
sin theta = 3 / squareroot of (10)
Substituting the values,
|T| = |r| x |F| sin theta => 100 = |0.6| x |F| x 3 / squareroot of (10)
|F| = (100 x squareroot of (10)) / 1.8
|F| = (1000 / 18) x squareroot of (10)
Magnitude of force |F| = 55.55 x squareroot of (10)</span>
