Answer:
(D)
Step-by-step explanation:
From the figure, we have
The coordinates of the point F are: (-4,1).
The coordinates of the point G are: (0,-2)
The coordinates of the point J are: (0,4) and
The coordinates of the point H are: (-4,-2).
Now, the slope of the line FG is :



And, the slope of the line HJ is:



Now, 

which is not possible, thus They are not perpendicular because their slopes are not negative reciprocals.
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
X< -10/3
Interval Notation:
(-∞, - 10/3)
Hope this is right :)
Answer:
there would be a 1-51 chance most likely
Step-by-step explanation:
Answer:
Tenacious tennis: y=5x+120
Totally Tennis: 8x
Toys r us: y=20x
Lego club: y=17x+36
Step-by-step explanation:
y=cost x= tennis court usage charge
Tenacious tennis: y=5x+120
Totally Tennis: 8x
8.)
y=cost x=lego set
Toys r us: y=20x
Lego club: y=17x+36
Answer:
Given that <ACB is congruent to <ABC we can infer that the triangle formed is an isosceles triangle. If B and C are both congruent and the distance from c and x and b and y are also congruent than the angles are congruent.
Step-by-step explanation: