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KatRina [158]
3 years ago
15

{This question has been deleted}

Mathematics
2 answers:
stiks02 [169]3 years ago
4 0

Answer:

this question isn't deleted yet

Slav-nsk [51]3 years ago
4 0

Answer:

hum

Step-by-step explanation:

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How do i deleted a question on here lol
shtirl [24]
I don’t think you can lol
8 0
3 years ago
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3x=y y=9 Solve for x.
sergejj [24]

Answer:

x=3

Step-by-step explanation:

3x=y y=9

fill y in with 9

3x=9

÷3  ÷3

x=3

6 0
3 years ago
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a square red rug has a purple square in the center. the side length of the purple square is x inches. the width of the red band
Bumek [7]

Answer:

Area of red band is (20x + 100) inch^{2}

Step-by-step explanation:

We know that area of square = side^{2}

Please refer to the attached figure, we have to calculate the area of red band.

Required area = Area of square <em>ABCD </em>- Area of <em>purple square </em>

Side of purple square = x

So, area of purple square = x^{2}

<em>ABCD </em>is a square with purple square at the center and there is symmetry in the figure.

So, width of red band towards both the end is 5 inches.

\Rightarrow \text{side of }ABCD = 5 + 5 +x = (x+10) inches

Required area = (x+10)^{2} - x^{2}

Using formula a^{2} - b^{2} = (a-b)\times (a+b)

\Rightarrow (x+10-x)(x+10+x)\\\Rightarrow (10)(2x+10)\\\Rightarrow (20x+100)

Hence, Area of red band is (20x + 100) inch^{2}

5 0
3 years ago
Factor completly 4x^2 +8x -5
DaniilM [7]

∑ Hey, jillianwagler ⊃

Answer:

\left(2x-1\right)\left(2x+5\right)

Step-by-step explanation:

<u><em>║Given info║:</em></u>

<em>Factor completely: </em>4x^2 +8x -5

<u><em>Solution~:</em></u>

<em>Breaking the expression~:  </em>\left(4x^2-2x\right)+\left(10x-5\right)

<em>Factor out 2x from 4x² -2x : 2x(2x-1)</em>

<em>Factor out 5 from 10x - 5 : 5(2x - 1)</em>

<em>Put together: </em>=2x\left(2x-1\right)+5\left(2x-1\right)

Factor out 2x - 1: =\left(2x-1\right)\left(2x+5\right)

<u><em>xcookiex12</em></u>

<em>8/19/2022</em>

4 0
2 years ago
Please solve!!!!!!!!!!!!!!
Ainat [17]
The answer is b. 7 is greater than or equal to 6.
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3 years ago
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