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2 years ago

13

Parallel Lines never intersect because...

1 answer:

Bingel [31]2 years ago

8 0

Answer:

Parallel lines are lines that never intersect because they have the same slope (m). So, this means that they only possible difference in there equations is the y-intercept (b). ... The slope in each equation is one-half, but each equation has a different y-intercept.

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Please help me with this!!!

guajiro [1.7K]

Answer: 41

Step-by-step explanation:

9*(-2)*(-2) - 4*(-2) - 3 = 9*4 + 8 - 3 = 36 + 5 = 41

3 0

3 years ago

Which baby is growing at a faster rate?

Paha777 [63]

Answer:

A.) Baby A

The first one

Step-by-step explanation:

have a good day

6 0

2 years ago

Read 2 more answers

Please anyone help me The measure of an angle is five times the measure of its supplementary angle. What is the measure of each

Radda [10]

Answer:

150 and 30

Step-by-step explanation:

Hello!

Supplementary angles are angles that when added up equal 180

Which can be shown by

x + x = 180

Since one has to be 5 times bigger we put a 5 in front of one of the x's

5x + x = 180

5x is an angle and x is the other

Now we solve for x

5x + x = 180

Combine like terms

6x = 180

Divide by 6

x = 30

Now we put that into each angle

5(30) = 150

30

The answer is 150 and 30

Hope this Helps!

5 0

3 years ago

Read 2 more answers

Extrano a mi sobrina, what does the underlined word mean

Simora [160]

Answer:

I miss my niece

Step-by-step explanation:

it's the meaning of that hope U get it ...

6 0

2 years ago

Solve using the quadratic formula 3x^2+11x+5=0

storchak [24]

Answer:

$3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}$

Decimal:

$(x = -0.53162..., x = -3.13504...)$

Step-by-step explanation:

$3x^2+11x+5=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}$

$x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}$

The solutions to the quadratic equation are:

$x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0

3 years ago