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Maksim231197 [3]
3 years ago
9

Simplify expression 2i(4.5-20i)3i

Mathematics
1 answer:
Margaret [11]3 years ago
3 0

Answer:

-27+120i

Step-by-step explanation:

that is the answer

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Use the distance formula to find The distance between the points (-1 ,3) and (2,6) write you answear as a square root, do not gi
olga nikolaevna [1]

Answer:

d = 3\sqrt{2}

Step-by-step explanation:

The distance formula is d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}  -y_{1} )^{2}   }

Plug in the points.

d = \sqrt{(2-(-1))^{2}+(6  -3 )^{2}   }

Solve

d = \sqrt{18}

Simplify by separating 18 into 9x2

d = \sqrt{9(2)}

Take the square root of 9 to finish simplifying

d = 3\sqrt{2}

6 0
3 years ago
For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?​
konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1

After solving we get value of y=-1

Now putting in eq(1) to get value of x

x+2y=0\\x+2(-1)=0\\x-2=0\\x=2

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3

So, After solve the equations we get value of k=3

4 0
3 years ago
If f(x)=4x^2+1 and g(x)=x^2-5 find (f+g)
lutik1710 [3]
Given:
f(x) = 4x² + 1
g(x) = x² - 5

Then
(f + g)(x) = 4x² + 1 + x² - 5
              = 5x² - 4

Answer: 5x² - 4
3 0
3 years ago
Read 2 more answers
Cierra has 3 more than one half as many purses as Aisha define the variable and write an expression to represent the number of p
77julia77 [94]
Cierra has 9 purses..
4 0
3 years ago
A semicircle with diameter PQ sits on an isosceles triangle PQR to form a region shaped like a two-dimensional ice- cream cone,
Ksivusya [100]

The limit of a(x)/b(x) as x approaches 0 is gotten as;

lim a(x)/b(x); x→0 = 0

  • The image showing the semi circle and isosceles triangle is missing and so i have attached it.

  • Formula for <em>area</em> of a semi circle is;

a(x) = A = ¹/₂πr²

  • <em>Area</em> of triangle is;

b(x) = A =  ¹/₂ × base × height

  • From the image, ∠PQR = θ

Thus; a(x) = ¹/₂π(10 sin (θ/2))²

a(x) =  ¹/₂π(100 sin² (θ/2))

Similarly;

b(x) =  ¹/₂(20 sin (θ/2)) × (10 cos (θ/2))

b(x) = 100 sin (θ/2) cos (θ/2)

  • Thus;

a(x)/b(x) = ¹/₂π(100 sin² (θ/2)) ÷ 100 sin (θ/2) cos (θ/2)

100 will cancel out and the sin (θ/2) at the denominator will be eradicated

upon further simplification to give;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2)

In trigonometry, we know that; tan θ = sin θ/cos θ

Thus;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2) =  ¹/₂π(tan (θ/2))

We want to find the limit as θ approaches <em>zero.</em>

Thus;

lim θ → 0 =  ¹/₂π(tan (0/2))

⇒ ¹/₂π tan 0

⇒ 0

Read more at; https://brainly.in/question/9387458

3 0
2 years ago
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