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spin [16.1K]
4 years ago
5

I REALLY NEED SOMEONES HELP ON THIS PLEASE!! I NEED THIS DONE TODAY!

Mathematics
1 answer:
Rufina [12.5K]4 years ago
8 0
The 5 in x - 5 needs to be negative in the table. So, change that and make everything else in that row negative.

You are then left with 3x^2 + x - 15x - 5

Simplify to 3x^2 - 14x - 5



Please consider marking this answer as Brainliest to help me advance. If you have any questions, please let me know.
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Which is equivalent to the following expression? (2x - 1)(x + 3)
Novay_Z [31]

Answer:

2x2+5x−3

Step-by-step explanation:

Expand the polynomial using the FOIL method.

5 0
3 years ago
Solve by multiplying digits of value and filling in zeros:<br><br> 200 x 80 x 60
shusha [124]

Answer:

down below:)

Step-by-step explanation:

200 times 80 times 60 is:

200 times 80 is 16000

16000 times 60 is 960000

4 0
3 years ago
6200.07 = 6.2 × 10^c + 7 × 10^d<br> Work out the values of c and d.
Nina [5.8K]

Answer: We have c = 3 and d = -2

Step-by-step explanation:

We want to solve the equation:

6200.07 = 6.2x10^c + 7x10^d

First, we can separate the left number into two pieces:

6200.07 = 6200 + 0.07 = 6.2x10^c + 7x10^d

Now we can solve it as:

6200 = 6.2x10^c

6200/6.2 = 10^c

1000 = 10^c

now we can use that if y = a^x, then ln(y)/ln(a) = x

here we have:

c = ln(1000)/ln(10) = 3

and

0.07 = 7x10^d

0.07/7 = 10^d

0.01 = 10^d

d = ln(0.01)/ln(10) = -2

 

3 0
4 years ago
Read 2 more answers
A sugar solution was made by mixing 7 ml of a 50% sugar solution and 3 ml of a 80% sugar solution. Find the concentration of the
pochemuha
7 * 0.5 + 3 * 0.8 = 3.5 + 2.4 = 5.9 

<span>5.9/10 X 100 = 59%


</span><span>59% concentration of new mixture</span>
4 0
3 years ago
On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming
Anvisha [2.4K]

Answer:

L(t) = 1,100*(1+0.87)^{\frac{t}{2.4}}

Step-by-step explanation:

The locust population grows according to an exponential model with the following general formula:

L(t) = L_0*(1+r)^{\frac{t}{T}}

Where 'L0' is the initial locust population, 'r' is the increase rate after 'T' days, and 't' is the time passed, in days.

Applying the given data, the function that models the locust population t days since the first day of spring is:

L(t) = 1,100*(1+0.87)^{\frac{t}{2.4}}

3 0
3 years ago
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