Find the median, first quartile, third quartile, and interquartile range of the data.
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Answer:
Step by Step
This is probably the most difficult problem in elementary Geometry. I stopped counting after about 20 steps. The trick is to follow a very carefully constructed diagram which looks simple enough until you start using it.
Givens
- Triangle ABC with 2 equal sides AB and AC.
- BC is the third side and is not equal to either of the other 2.
Answer:
The line passing through the given points is:
in its slope-intercept form
Step-by-step explanation:
Start by finding the slope of the segment that joins the two given points using the slope formula:
which for our case renders:
Now we can find the y-intercept by using any one of the given points in the general slope-intercept form of a line with this slope:
Therefore, the equation of the line becomes:
Observe that as the series progresses, the term decreases by 1/4. To show this, observe the first four terms of the series below.
-200 = (1/4)(-800)
-50 = (1/4)(-200)
-12.5 = (1/4)(-50)
Since we have a common ratio, r, of 1/4, we can use the properties of a geometric series to find the 8th term of the series.
Recall that to find the sum of the nth term of a geometric series, we have
where a is the first term of the series and r is the ratio.
So, for the first eight terms, we have
Therefore, the sum of the 8th series is approximately -1066.65.
Answer: -1066.65
-200 = (1/4)(-800)
-50 = (1/4)(-200)
-12.5 = (1/4)(-50)
Since we have a common ratio, r, of 1/4, we can use the properties of a geometric series to find the 8th term of the series.
Recall that to find the sum of the nth term of a geometric series, we have
where a is the first term of the series and r is the ratio.
So, for the first eight terms, we have
Therefore, the sum of the 8th series is approximately -1066.65.
Answer: -1066.65