A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:

Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1





We know that the time is always positive, therefore 
when the stuntman is 10m above the ground.
height
Put height value in equation 1







Therefore ,time interval of camera film him is 
First you do 3a^4(2b^6c^3)^2
=12a^4b^12c^6
Answer:
The answer is 8 : 22, 12:33 as they are two equelivant ratios 11 and 4
Answer:
The discriminant b2−4ac < 0, the equation has no real number solutions, it has complex solutions
Step-by-step explanation:
9x² - 4x + 1 = 0 ax² + bx + c = 0
The discriminant: b² - 4ac = (-4)² - 4*9*1 = 16 - 36 = -20
b2−4ac < 0, the equation has no real number solutions, it has complex solutions