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JulijaS [17]
2 years ago
14

Help asap please,i don’t get the question

Mathematics
1 answer:
mario62 [17]2 years ago
3 0

Answer:

see below

Step-by-step explanation:

I do not know what the 'given expression' is, bu the three UN-highlighted expressions in each question 1 and 2  are equivalent

  Only the highlighted one is not equiv to the other three

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Jake is wrapping a gift that is in a box with the following dimensions.
nordsb [41]

Answer: 8

Step-by-step explanation: first multiply 12x4x8 for jakes gift. that is 384

then make each of the dimensions twice as large. so havanas dimensions would be. 24x8x16

24x8x16=3,072

last divide 3,072 by 384 and the answer would be 8

Havana's box is 8 times larger.

4 0
2 years ago
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HELP ME THIS MY LAST QUESTION PLEASE!!!!!!!!!!!!!!!!!!!!!!!
krok68 [10]

Answer: c

Step-by-step explanation:

7 0
3 years ago
A pizza shop sells three sizes of pizza, and they track how often each size gets ordered along with how much they profit from ea
777dan777 [17]

Answer:

The mean and standard deviation of Y is $6.56 and $2.77 respectively.

Step-by-step explanation:

Consider the provided information.

Let Y represent their profit on a randomly selected pizza with this promotion.

The company is going to run a promotion where customers get $2 off any size pizza.

Therefore, Y=\text{Profit}-\$2

Y=X-\$2

So the mean will be reduced by 2.

\mu_Y=\mu_X-\$2

\mu_Y =\$ 8.56 - \$2

\mu_Y =\$6.56

If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.

Therefore \sigma_Y=\sigma_X=2.77

Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.

3 0
3 years ago
A study was conducted and two types of engines, A and B, were compared. Fifty experiments were performed using engine A and 75 u
USPshnik [31]

Answer:

a) -6 mpg.

b) 2.77 mpg

c) The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem, and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Gas mileage A: Mean 36, standard deviation 6, sample of 50:

So

\mu_A = 36, s_A = \frac{6}{\sqrt{50}} = 0.8485

Gas mileage B: Mean 42, standard deviation 8, sample of 50:

So

\mu_B = 42, s_B = \frac{8}{\sqrt{50}} = 1.1314

Distribution of the difference:

Mean:

\mu = \mu_A - \mu_B = 36 - 42 = -6

Standard error:

s = \sqrt{s_A^2+s_B^2} = \sqrt{0.8485^2+1.1314^2} = 1.4142

A. Find the point estimate.

This is the difference of means, that is, -6 mpg.

B. Find the margin of error

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = zs = 1.96*1.4142 = 2.77

The margin of error is of 2.77 mpg

C. Construct the 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results(5 pts)

The lower end of the interval is the sample mean subtracted by M. So it is -6 - 2.77 = -8.77 mpg

The upper end of the interval is the sample mean added to M. So it is -6 + 2.77 = -3.23 mpg

The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

8 0
2 years ago
A box of uncooked spaghetti cost $0.1369 per ounce. how much is this cost to the nearest cent?
AlladinOne [14]
The cost to the nearest sent is 0.14

This is because you can round the .136 up to the nearest hundredths place.
3 0
3 years ago
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