Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Option B is the correct answer
Answer:
Angle: 22.5 deg, Complement: 67.5 deg, Supplement: 157.5 deg
Step-by-step explanation:
22.5 is 1/3 of 67.5
so compliment is 67.5.
Supplement is just adding another angle so I chose 7.
I did 22.5 x 7 = 157.5
Another example would be:
Angle: 10 deg, Complement: 30 (because 10 x 3), Supplement: 70 (because 10 x 7)
Hope this helps :)
Answer:
The page numbers are 36 and 37.
Step-by-step explanation:
n + (n + 1) = 73
2n + 1 = 73
n = (73 - 1)/2
= 72/2 = 36
Answer:
See the image.
Step-by-step explanation:
Constant balance in a bank account signifies that the balance in the account remains constant throughout time.
That is, it did not rise or diminish with time.
As a result, the graph of such a circumstance is a horizontal line parallel to the Time period axis.