How would you solve 200 x 30/100? Please give instructions in how you did so.
1 answer:
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Answer:
A. 5,8,12, side lengths can form a triangle.
B. 20, 18, 2, side lengths can not form a triangle.
C. 15, 26 , 9, side lengths can not form a triangle.
D. 4.75, 12.25, 16.25, side lengths can form a triangle.
Step-by-step explanation:
We are given three sides in options A, B , C and D.
We need to check if the given sides would form a triangle or not.
Note: Sum of two sides is always greater than third sides in a triangle.
So, we need to check the sum of two sides of given sides length to check if sum is greater than third side length.
A. 5,8,12.
5+8 is greater than 12.
5+12 is greater than 8.
12+8 is greater than 5.
Therefore A. 5,8,12, side lengths can form a triangle.
B. 20, 18, 2
18+2 is not greater than 20.
Therefore B. 20, 18, 2, side lengths can not form a triangle.
C. 15, 26 , 9
15+9 is less than 26.
Therefore C. 15, 26 , 9, side lengths can not form a triangle.
D. 4.75, 12.25, 16.25.
4.75+12.25 is greater than 16.25.
4.75+16.25 is greater than 12.25.
12.25+16.25 is greater than 4.75.
Therefore D. 4.75, 12.25, 16.25, side lengths can form a triangle.
