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timofeeve [1]
3 years ago
12

Which of the following scenarios demonstrates sampling bias? (A) To estimate the ethnic background distribution of residents of

his town, Adam collects data from 1000 randomly selected town residents by using a random number generator. (B) Lisa wants to estimate the male to female ratio of the residents of her city. She collects data by recording the sex of every soth resident after selecting a random starting point on a list of residents (C) Jean wants to estimate the mean amount of money spent on clothes per week by mall shoppers. She collects data from every 10th person entering a clothing store at the mall.(D) To estimate the mean number of classes that students take at his university, Frank collects data from a randomly selected proportionate number of students from each grade level.
Mathematics
1 answer:
ankoles [38]3 years ago
6 0

Answer:

Option C.

Step-by-step explanation:

Sampling bias is a problem during the initial data gathering step of a survey.

When the first step is wrong, then the survey cannot produce non biased results.

The problem occurs when the design of the study is wrong the data collection procedure is wrong.

So, here answer seems C, because the starting point is not selected at random in this survey.

(C) Jean wants to estimate the mean amount of money spent on clothes per week by mall shoppers. She collects data from every 10th person entering a clothing store at the mall.

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Write in terms of inequalities: (-13,4]
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Answer:

  -13 < x ≤ 4

Step-by-step explanation:

The round bracket means the lower limit is not included in the interval. The square bracket means the upper limit is included.

  -13 < x ≤ 4

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2 years ago
The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle
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Answer: 3.217 & 12.434

Step-by-step explanation:

If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.

Hence, the length is 2w+6.

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

A=w(2w+6)

We can also substitute 40 in for A as it's given in the question.

40 = w(2w+6)

Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get

40 = 2w^2+6w

We can make the equation simpler by dividing both sides by 2.

20 = w^2+3w

Subtracting both sides by 20 will make the left-hand side 0.

0=w^2+3w-20

Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}

w= \frac{-3\pm\sqrt{9+80}}{2}

w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}

Since the second solution results in a negative number, it cannot be the length of w.

w=\frac{-3+\sqrt{89}}{2}\approx3.217

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

l=2(3.217)+6

l=12.434

The length of this rectangle is 12.434 cm.

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