Answer:
Step-by-step explanation:
Multiply each term of the first polynomial with the second polynomial. Then combine the like terms.
(3a<em>² + 5a - 2)* (5a² -3a + 4)</em>
<em> = 3a² *(5a² -3a + 4) + 5a*(5a² -3a + 4) - 2*(5a² -3a + 4)</em>
<em>=3a²*5a² - 3a*3a² + 4*3a² + 5a*5a² - 3a*5a + 4*5a + 5a²*(-2) - 3a*(-2) + 4*(-2)</em>
<em>=15a⁴ - 9a³ + 12a² + 25a³ - 15a² + 20a - 10a² + 6a - 8</em>
<em>= 15a⁴ </em><u><em>- 9a³ + 25a³</em></u><em> +</em><u><em> 12a² - 15a² - 10a²</em></u><em> +</em><u><em> 20a +6a </em></u><em>- 8</em>
<em>= 15a⁴ + 16a³ - 13a² +26a - 8</em>
Answer:
3 (10-a) = 4 i think
Step-by-step explanation:
Answer:
your teacher is crazy about she think you are smart
Answer:
C
Step-by-step explanation:
look up rules of multiplying radicals.
You can multiply the radicands (the number inside the square root) then take the square root of the new number.
3*21 = 63
Factor 63 into 3*3*7
Pull out 3^2 from inside the square root
leaves you with 3sqrt7 or answer C
no you cannot conclude that state c costs more than a and b because you do not know the value of state a and b
