Answer:
![\large\boxed{\ln\sqrt[3]{e^4}=\dfrac{4}{3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cdfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\text{Use}\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\ln a^n=n\ln a\\\\\ln e=1\\-----------\\\\\ln\sqrt[3]{e^4}=\ln e^\frac{4}{3}=\dfrac{4}{3}\ln e=\dfrac{4}{3}\cdot1=\dfrac{4}{3}](https://tex.z-dn.net/?f=%5Ctext%7BUse%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Cln%20a%5En%3Dn%5Cln%20a%5C%5C%5C%5C%5Cln%20e%3D1%5C%5C-----------%5C%5C%5C%5C%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cln%20e%5E%5Cfrac%7B4%7D%7B3%7D%3D%5Cdfrac%7B4%7D%7B3%7D%5Cln%20e%3D%5Cdfrac%7B4%7D%7B3%7D%5Ccdot1%3D%5Cdfrac%7B4%7D%7B3%7D)
Answer:
Peter swam 12 hours, Pam swam 6
Step-by-step explanation:
Pam = x
Peter = y
y = 2x (this is because Peter swam twice as much)
y + x = 18 (this is because they both swam a total of 18 hours)
2x + x = 18 (substitute for y)
3x = 18
x = 6 (pam)
Now, I just need to substitute x = 6 into original equation.
y = 2(6)
y = 12 (peter)
DEF is a isosceles right triangle, so DE =EF. apply Pythagoras:
DF² = DE² + EF² , BUT DE = DF .then DB² = 2DE² = 28²
DE² = 28/2 = 14 and DE = √14 = 3.71 ≈3.7
Answer:
x = 6(x - 2)
Step-by-step explanation:
His age now is x.
His age 2 years ago was x - 2.
x = 6(x - 2)
