Complementary angles = 90
x+y =90
y=x+24
substitute this in to the equation
x+x+24=90
2x+24=90
subtract 24 from each side
2x = 66
divide by 2
x=33
y = 33+24
y=57
Answer: 33, 57
Answer:
TRUE
The 7 is in the hundredths place
The 0 is in the tenths place
The 8 is in the thousandths place
Step-by-step explanation:
Answer:
Since
x
is on the right side of the equation, switch the sides so it is on the left side of the equation.
x
2
−
2
x
+
3
=
G
(
x
)
Multiply
G
by
x
.
x
2
−
2
x
+
3
=
G
x
Subtract
G
x
from both sides of the equation.
x
2
−
2
x
+
3
−
G
x
=
0
Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)
2
a
Substitute the values
a
=
1
,
b
=
−
2
−
G
, and
c
=
3
into the quadratic formula and solve for
x
.
−
(
−
2
−
G
)
±
√
(
−
2
−
G
)
2
−
4
⋅
(
1
⋅
3
)
2
⋅
1
Simplify.
Tap for more steps...
x
=
2
+
G
±
√
G
2
+
4
G
−
8
2
The final answer is the combination of both solutions.
x
=
2
+
G
+
√
G
2
+
4
G
−
8
2
x
=
2
+
G
−
√
G
2
+
4
G
−
8
2
Step-by-step explanation:
Answer:
158 m²
Step-by-step explanation:
I made this into 3 rectangles.
Figure 1:
9•8=72
The 9 is from the 13 m side, but I've taken 4 m off from the overlapping square.
Figure 2:
6•7=42
The 7 is from the 10 m side, but I've taken 4m off from the overlapping square again.
Remaining Area:
If you extend the lines into figures 1 and 2 from the top left corner and bottom right corner vertically, you will get a rectangle that is (11 m) x (4 m). This is not yet accounted for.
11•4=44
Add together: 72 + 42 + 44 = <u>158</u>
*Note: You could also find the area of the squares a much easier way by subtracting the overlapping part after finding the area of both figures , but this is how I did it*
Boys: x
gilrs: y
From the text of the task:
Replacing x:
So there are 28 girs and 20 boys
