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Brums [2.3K]
3 years ago
5

Your mom opened a college fund for you when you were born. The fund had an annual interest rate of 2.5%. When you turned 18, the

account had earned $4,275 in interest. What was the amount your mom deposited when you were born? Use the formula: I = Prt.
Mathematics
1 answer:
Scilla [17]3 years ago
3 0
Given:
Interest = 4,275
interest rate = 2.5%
term = 18 years
Principal = ?

Interest = Principal * interest rate * term
4,275 = P * 2.5% * 18
4,275/ (2.5% * 18) = P
4,275 / 0.45 = P
9,500 = P

Your mom deposited 9,500 when you were born.
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Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

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So it has 2 real number solutions.

4. a=1, b=-2, c=-8

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5 0
3 years ago
Read 2 more answers
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3n+4=
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4 0
3 years ago
Read 2 more answers
(0.1296)^3/4 of law of indices plz step by step​
Serjik [45]

Answer:

\boxed {\frac{27}{125}}

Step-by-step explanation:

Solve the following expression:

(0.1296)^{\frac{3}{4}}

-Calculate 0.1296 to the power of \frac{3}{4}:

(0.1296)^{\frac{3}{4}}

\boxed {\frac{27}{125}}

Therefore, the final answer is \frac{27}{125}.

3 0
3 years ago
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