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Finger [1]
3 years ago
13

From point a travel 12 km south and 10 km west then travel 5 km north how far r u from point a

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

Answer:17

Step-by-step explanation:

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What is the equation of the line in the graph?
Verizon [17]
Well, we can see that the y-intercept is (0, -4) which means that the line must be:

y=mx-4

And since only one answer has -4 as the y-intercept, y=x-4 is the answer :P
8 0
3 years ago
Read 2 more answers
I really need help with this ... I hope someone can help!
viva [34]

9514 1404 393

Answer:

  ∠B = 53°

  ∠C = 127°

  ∠D = 127°

Step-by-step explanation:

The trapezoid is isosceles, as indicated by the hash marks on sides AD and BC. This means it is symmetrical about the vertical center-line. Angles on the right will have the same measures as the symmetrical angles on the left.

So, you know immediately that ∠B = ∠A = 53°.

Because AB ║ DC, ∠A and ∠D are supplementary. That is, ...

  ∠D = ∠C = 180° -53°

  ∠D = ∠C = 127°

4 0
2 years ago
Which angles are supplementary to∠4? Select all that apply.
andrezito [222]

9514 1404 393

Answer:

  B, D, E

Step-by-step explanation:

All of the acute angles are congruent to each other. All of the obtuse angles are supplementary to them and are also congruent to each other. Angles 2, 3, 6, 7 are supplementary to angle 4. The ones on the list of choices are ...

  ∠2, ∠6, ∠7

6 0
3 years ago
Subtract<br><br>40(-32-40-25)<br>please show how you will do that (step by step)​
sergeinik [125]

Answer:

-3880

Step-by-step explanation:

40(-32-40-25)\\40(-72-25)\\40(-97)\\-3880

Please give brainliest if this answer satisfies your question.

4 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Karo-lina-s [1.5K]

Let us find the co ordinates of each vertex of the triangle .

Vertex A ( in firs second quadrant) = ( -5 ,3)

vertex B in third quadrant = ( -5, -5)

vertex C in fourth quadrant = ( 4, -2)

let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0

AB= 8

BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90

BC = 9.48

AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106

AC= 10.29

Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77

8 0
3 years ago
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