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Ksju [112]
4 years ago
7

-1+5/4x=-16 What number is x representing?

Mathematics
1 answer:
ValentinkaMS [17]4 years ago
5 0

Answer:

x = -12,

Step-by-step explanation:

-1 + 5/4x = -16

5/4 x = -16 + 1

5/4 x = -15

x = -15 * 4/5

x = -12.

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Solve for p if 2|p| = 4
ehidna [41]
2p = 4
p = 2

-2p = 4
p = -2

answer p = -2 and p =2
3 0
4 years ago
Read 2 more answers
Solve for x <br> please i give brainliest
SOVA2 [1]

Answer:

I dont know sorry

Step-by-step explanation:

3 0
3 years ago
Answer the following equations:
Andrew [12]

Step-by-step explanation:

3(t+5) = 9

3t+15 = 9

3t = -6

t = -2

2(f-7) = -10

2f - 14 = -10

2f = 4

f = 2

-(c - 9) = 4

-c + 9 = 4

-c = -5

c = 5

-6(2t + 8) = -84

-12t - 48 = -84

-12t = -36

12t = 36

t = 3

-10 (s + 2) = -57

-10s - 20 = -57

-10s = -37

s = 3.7

7(3w + 8)/3 = -9

By cross multiplication,

7(3w + 8) = -27

21w + 56 = -27

21w = -83

w = -3.95

35/5 = (F - 32)/9

7 = (F - 32)/9

By cross multiplication,

63 = F - 32

63 + 32 = F

95 = F

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>

7 0
2 years ago
Find the mean of the data<br><br><br><br> The mean is ___visits to your website.
lorasvet [3.4K]
To find the mean you first add all the numbers up you get each day
12+16+0+8+31+28+17=112
Than you divided it by how many days there are...
112/7=16
So the mean is 16
3 0
3 years ago
Read 2 more answers
1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

3 0
4 years ago
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