If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
correct answer is 0.0000010075
<em>Denote x2 by y.
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<em>(x2-3)7=(y-3)7
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<em>This is a binomial expansion in y, and you want the coefficient of y4 because y4=x8
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<em>You have 7 terms of (y-3) in (y-3)7. To get the fourth power of y, you need to choose y from four of the terms. The number of ways you can do this is the combinations of 7 things taken 4 at a time. This is:
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<em>7!/(4!3!)=35</em>
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<em>So, the coefficient of x8 in the given expansion will be 210.</em>
<em>HOPE IT HELPS</em>
<em>THANK YOU </em>
Question 1:
A = w * l
A = 5432m^2
l = 97
A / l = w
5432 / 97 = 56
w = 56
Question 2:
Perimeter of rectangle = 2w + 2l
P = 336
w = 79
P - 2w = 2l
336 - 158 = 178
178 / 2 = 89
l = 89
2.74 liters since 1000mL is a liter.
