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svlad2 [7]
3 years ago
13

jonas has 8 sponsors for the school walk-a-thon. Maura has 3 times as many sponsors as Jonas. Treton has 1/4 as many sponsors as

Jonas. ow many sponsors does Maura have?
Mathematics
2 answers:
diamong [38]3 years ago
4 0
Jonas has 8 sponsors
Maura has 24 sponsors
Treton has 2 sponsors
kirill [66]3 years ago
3 0
Jonas has 8, Maura has 24, and Treton has 6 I think. Hope it helps :)
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aliya0001 [1]
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There are 70 sixth graders at Wilson Middle School. Only 40% of the sixth graders will attend the morning assembly. How many six
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jenyasd209 [6]

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6 0
3 years ago
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BaLLatris [955]

Answer:

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax

​2

​​ +bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a

​2a

​

​−b+√

​b

​2

​​ −4ac

​

​​

​​ )(x−

​2a

​

​−b−√

​b

​2

​​ −4ac

​

​​

​​ )

2 In this case, a=1a=1, b=-2b=−2 and c=-2c=−2.

(x-\frac{2+\sqrt{{(-2)}^{2}-4\times -2}}{2})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times -2}}{2})(x−

​2

​

​2+√

​(−2)

​2

​​ −4×−2

​

​​

​​ )(x−

​2

​

​2−√

​(−2)

​2

​​ −4×−2

​

​​

​​ )

3 Simplify.

(x-\frac{2+2\sqrt{3}}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

​2

​

​2+2√

​3

​

​​

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

4 Factor out the common term 22.

(x-\frac{2(1+\sqrt{3})}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

​2

​

​2(1+√

​3

​

​​ )

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

5 Cancel 22.

(x-(1+\sqrt{3}))(x-\frac{2-2\sqrt{3}}{2})(x−(1+√

​3

​

​​ ))(x−

​2

​

​2−2√

​3

​

​​

​​ )

6 Simplify brackets.

(x-1-\sqrt{3})(x-\frac{2-2\sqrt{3}}{2})(x−1−√

​3

​

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

7 Factor out the common term 22.

(x-1-\sqrt{3})(x-\frac{2(1-\sqrt{3})}{2})(x−1−√

​3

​

​​ )(x−

​2

​

​2(1−√

​3

​

​​ )

​​ )

8 Cancel 22.

(x-1-\sqrt{3})(x-(1-\sqrt{3}))(x−1−√

​3

​

​​ )(x−(1−√

​3

​

​​ ))

9 Simplify brackets.

(x-1-\sqrt{3})(x-1+\sqrt{3})(x−1−√

​3

​

​​ )(x−1+√

​3

​

​​ )

7 0
3 years ago
Read 2 more answers
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