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Margarita [4]
3 years ago
9

Describe a physical change

Chemistry
1 answer:
Kaylis [27]3 years ago
8 0
A chemical change results from a chemical reaction, while a physical change is when matter changes forms but not chemical identity. Examples of chemical changes are burning, cooking, rusting, and rotting. Examples of physical changes are boiling, melting, freezing, and shredding.




Hope this helps :)
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What will litmus paper turn when it reacts with sodium nitrate?​
castortr0y [4]
A solution of sodium nitrate will get make litmus paper wet. A solution of NaNO3 is neutral. Therefore, there is no change in color.
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3 years ago
write the names of the following compounds. 1) iron + sulphur . 2) manganese + oxygen. aluminium + sulphur​
Vlada [557]

Answer:

  1. FeS
  2. MnO₂
  3. Al₂S₃

Explanation:

<u>1) Iron + Sulphur = ?</u>

→ Iron sulfide

<u>2) Manganese + Oxygen = ?</u>

→ Manganese dioxide

<u>3) Aluminium + Sulphur = ?</u>

→ Aluminium sulfide

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A mole of lead will be heavier than a mole of oxygen because
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A certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 60.00 gram sample of the alcohol p
marin [14]

Answer:

C_2H_6O

Explanation:

The first step is the <u>calculation of the moles</u> of H_2O and CO_2, so:

114.6~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=2.6~mol~of~CO_2

70.44~g~H_2O\frac{1~mol~H_2O}{18~g~H_2O}=~3.9~mol~H_2O

Now, in 1 mol of CO2 we have 1  mol of C and in 1 mol of H_2O we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to <u>calculate the grams of C and O</u> and then do the <u>substraction</u> form the initial amount, so:

2.6~mol~CO_2\frac{1~mol~C}{1~mol~CO_2}\frac{12~g~C}{1~mol~C}=31.25~g~of~C

3.9~mol~H_2O\frac{2~mol~H}{1~mol~H_2O}\frac{1~g~H}{1~mol~H}=7.82~g~of~H

Total~grams=~31.25~+~7.82=39.08~g

grams~of~O=60.00~g-~39.08~g=20.92~g~of~O

Now we can <u>convert the grams</u> of O to moles, so:

20.92~g~of~O\frac{1~mol~O}{16~g~O}=1.30~mol~O

The next step is to divide all the mol values by the <u>smallest one</u>:

O=\frac{1.30~mol~O}{1.30~mol~O}=~1

C=\frac{2.6~mol~C}{1.30~mol~O}=~2

H=\frac{7.82~mol~H}{1.30~mol~O}=6

Therefore the formula is C_2H_6O

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3 years ago
The chart indicates the time, speed, and velocity of five runners.
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Answer:

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Explanation:

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