Answer:
Reactants are favored over products in the reaction
Explanation:
Answer:
The main function sis the 2nd one and the substance provides the first 1.
Explanation:
Hope you finish the rest on your own, have fun!
The correct answer is 0.15.
We are aware that there is 0.05 mol of an unidentified hydrocarbon we will refer to as "X" and that its burning produces 6.6 g of carbon dioxide and 3.6 g of water.
These quantities might be converted to moles by applying the following formula:
amount= mass/ relative atomic mass
Thus, the following equation may be written for H2O: moles = 3.6 / 18 = 0.2 and for CO2: moles = 6.6 / 44 = 0.15.
0.05X + x'O2 = 0.15CO2 + 0.2H2O
This may be made simpler by dividing through by 0.05 (this step is likely to be the most helpful to you), resulting in:
1 x + x O2 = 3 co2 + 4 H2O
The hydrocarbon must have been the source of all the carbon in the carbon dioxide and all the hydrogen in the water.
Accordingly, 4 x 2 = 8 moles of H and 3 x 1 = 3 moles of C.
There are 3/1 = 3 Cs and 8/1 = 8 Hs in one X molecule.
This clearly identifies C3H8 or propane as the hydrocarbon X (dividing by 1 seems unnecessary, but it illustrates the process to use if there were more than one mol of X in the first equation).
To learn more about number of moles of carbon dioxide refer the link:
brainly.com/question/12723070
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Answer: 7.8 moles of NaCl result from the complete reaction of 3.9 mol of 
Explanation:
To calculate the moles :
As 
is the excess reagent, is the limiting reagent as it limits the formation of product.
According to stoichiometry :
1 mole of gives = 2 moles of 
Thus 3.9 moles of will give=
of
7.8 moles of NaCl result from the complete reaction of 3.9 mol of
At STP, pure ethanol has density 0.789g/mL. 25 mL will have mass 25 (mL) * 0.789 (g/mL)=19.725 g. Round this to 19.7g for three significant figures.
(not fully sure if this is correct)
