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Tamiku [17]
3 years ago
9

When optically active (S)-2-methylcyclopentanone is treated with aqueous base, the compound loses its optical activity. Explain

this observation and draw a mechanism that shows how racemization occurs. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph. Collapse question part 21.55a Get help answering Molecular Drawing questions Get help answering Molecular Drawing questions. Draw (S)-2-methylcyclopentanone.
Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

See explanation and image attached

Explanation:

The first step in the reaction is the attack of the hydroxide ion from the base abstracting a proton from (S)-2-methylcyclopentanone.

The abstraction of a proton from water by the substrate yields the enol form in equilibrium with the keto form.

The product formed is racemic hence the optical activity of (S)-2-methylcyclopentanone is lost.

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A football is inflated to 12psi at 20°C What is the new pressure in the football
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Explanation:

Given: P_{1} = 12 psi,         T_{1} = 20^{o}C

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Formula used is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi

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2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y
Elden [556K]

Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

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As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>

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The mass is:

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