When optically active (S)-2-methylcyclopentanone is treated with aqueous base, the compound loses its optical activity. Explain
1 answer:
Answer:
See explanation and image attached
Explanation:
The first step in the reaction is the attack of the hydroxide ion from the base abstracting a proton from (S)-2-methylcyclopentanone.
The abstraction of a proton from water by the substrate yields the enol form in equilibrium with the keto form.
The product formed is racemic hence the optical activity of (S)-2-methylcyclopentanone is lost.
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Answer:
Explanation:
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That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.
The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.
The number to be dropped (3) is less than 5, so you drop it.