When optically active (S)-2-methylcyclopentanone is treated with aqueous base, the compound loses its optical activity. Explain
1 answer:
Answer:
See explanation and image attached
Explanation:
The first step in the reaction is the attack of the hydroxide ion from the base abstracting a proton from (S)-2-methylcyclopentanone.
The abstraction of a proton from water by the substrate yields the enol form in equilibrium with the keto form.
The product formed is racemic hence the optical activity of (S)-2-methylcyclopentanone is lost.
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Answer:
5.158 × 10²³ atoms K
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
33.49 g K
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of K - 39.10 g/mol
<u>Step 3: Convert</u>
<u /> = 5.15797 × 10²³ atoms K
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig figs and round.</em>
5.15797 × 10²³ atoms K ≈ 5.158 × 10²³ atoms K