Answer:
Vapor pressure for solution is 22.4 Torr
Explanation:
P° → Vapor pressure of pure solvent
P' → Vapor pressure of solution
Formula for lowering vapor pressure is: P° - P' = P° . Xm
Xm is the mole fraction. Let's determine it:
0.220 mol of solute + 3.70 mol of water = 3.92 total moles
Mole fraction for solute → 0.220 / 3.92 = 0.056
23.8 Torr - P' = 23.8 Torr . 0.056
P' = - ( 23.8 Torr . 0.056 - 23.8 Torr ) → 22.4 Torr
Every one mol of MgO is 6.022 x 10^23 molecules (Avogado’s Number) So, you multiply 2.082 mol of MgO with 6.022 x 10^23 molecules. Hope this helps!
Answer:
I believe it is the overseer of the operation
Answer:
See explanation and image attached
Explanation:
The compound SF4 is sulphur tetraflouride. It has a zero formal charge and has a total of 34 valence electrons.
The central atom in the molecule is sulphur in an sp3d hybridization state hence the molecule has a trigonal bipyramidal electron geometry. Since it is a molecule of the sort AX4E; it gives a see-saw molecular shape.
The structure of the molecule is shown in the image attached to this answer.
<span>No need to balance the equation... it's already balanced
MgBr2 + Cl2 -> MgCl2 + Br2 </span>