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3 years ago

40 POINTS GIVEN PLEADE ANYONE HELP I NEED IT ASAP MY SESSION WILL EXPIRE

2 answers:

8 0

Will put 8 ounce in the. up because first you subtract the 16 ounces the he used to fill his bottle which leaves you with 128 ounces and you will divide the 128 by the 16 cups to get x equals 8 ounces.

asambeis [7]3 years ago

7 0

Answer:

x=8

Step-by-step explanation:

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The length of a flag is 0.3 foot less than twice its width. if the perimeter is 14.4 feet longer than the width, find the dimens

dem82 [27]

3.0 by 3.6 would be the dimensions

3 0

3 years ago

F(x)= 3x + 5

Valentin [98]

Step-by-step explanation:

(3x+5)-(4x²-2)-(x²-3x+1)

= 3x+5-4x²+2-x²+3x-1

=6x+6-5x²

=-5x²+6x+6

5 0

2 years ago

What is the total displacement of a student who walks 3 blocks east, 2 blocks north, 1 block west, and then 2 blocks south?

aniked [119]

Answer:

two blocks east

Step-by-step explanation:

the north and south cancel out and then 3 blocks east - 1 block west = 2 blocks east

3 0

2 years ago

19) Given that f(x)x² - 8x+ 15x² - 25find the horizontal and vertical asymptotes using the limits of the function.A) No Vertical

Tems11 [23]

EXPLANATION

Since we have the function:

$f(x)=\frac{x^2-8x+15}{x^2}$

Vertical asymptotes:

$For\:rational\:functions,\:the\:vertical\:asymptotes\:are\:the\:undefined\:points,\:also\:known\:as\:the\:zeros\:of\:the\:denominator,\:of\:the\:simplified\:function.$

Taking the denominator and comparing to zero:

$x+5=0$

The following points are undefined:

$x=-5$

Therefore, the vertical asymptote is at x=-5

Horizontal asymptotes:

$\mathrm{If\:denominator's\:degree\:>\:numerator's\:degree,\:the\:horizontal\:asymptote\:is\:the\:x-axis:}\:y=0.$ $If\:numerator's\:degree\:=\:1\:+\:denominator's\:degree,\:the\:asymptote\:is\:a\:slant\:asymptote\:of\:the\:form:\:y=mx+b.$ $If\:the\:degrees\:are\:equal,\:the\:asymptote\:is:\:y=\frac{numerator's\:leading\:coefficient}{denominator's\:leading\:coefficient}$ $\mathrm{If\:numerator's\:degree\:>\:1\:+\:denominator's\:degree,\:there\:is\:no\:horizontal\:asymptote.}$ $\mathrm{The\:degree\:of\:the\:numerator}=1.\:\mathrm{The\:degree\:of\:the\:denominator}=1$ $\mathrm{The\:degrees\:are\:equal,\:the\:asymptote\:is:}\:y=\frac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}$ $\mathrm{Numerator's\:leading\:coefficient}=1,\:\mathrm{Denominator's\:leading\:coefficient}=1$ $y=\frac{1}{1}$ $\mathrm{The\:horizontal\:asymptote\:is:}$ $y=1$

In conclusion:

$\mathrm{Vertical}\text{ asymptotes}:\:x=-5,\:\mathrm{Horizontal}\text{ asymptotes}:\:y=1$

4 0

1 year ago

Is it true or false you get (2,12) after you solve 3x-1/2y=0?

klemol [59]

It's true that (2, 12) is a solution of 3x-1/2 y = 0 .

It's also true that (1, 6), (3, 18), (5, 30), (9, 54), (150, 900),
and (12 million, 72 million) are also perfectly correct solutions.

Any pair of numbers where the 'y' number is six times as much as
the 'x' number is a solution to that equation.

There are an infinite number of them.

5 0

3 years ago