Answer:
21 ways
Step-by-step explanation:
number = 7 digit
5 digit no = 52115
to find out
How many different seven-digit numbers
solution
first we need to place the two missing 3s in the number 52115
we consider here two cases
case 1 the two 3's appear separated (like 532135 or 3521135)
case 2 the two 3's appear together (like 5332115 or 5211533)
Case 1 we can see that number type as _5_2_1_1_5_
place 3's placeholders show potential locations
( type a ) for 3's separated we will select 2 of 6 place and place 3 in every location so we do this 6C2 = (15) ways
and (type b): again use same step as _5_2_1_1_5_
here 3s together for criterion and we will select 1 of the 6 place and place both 3s here and there are 6 ways.
so that here will be 15+6=21 ways
If 3 and 3 are separate so 6C2 = 15 ways
If 3 and 3 are together so there = 6 ways
= 15 + 6 = 21 ways
Answer: bag 1 40%
bag 2 25%
i think hope it helped
Step-by-step explanation:
Answer: c
Step-by-step explanation:
because to find the average is to add all your numbers up and to divide them by how many numbers you have
and the median is the finding the middle which is the average you line them up from lowest to greatest value and cross one off from the beginning and one from the end until you are left either one or two values
Answer:
11
Step-by-step explanation:
2 3/4 times 4 equals 11
