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3 years ago

I really need help please!! i don't understand!! Will mark brainliest!!

Mathematics

1 answer:

nikklg [1K]3 years ago

8 0

Answer:

They y axis runs up and down so on the verticle lind where is says -2 plotthe point.

If you dont understand let me know and i will find a way to give your points back

Step-by-step explanation:

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Match the equation with the data set. ITEM BANK: Move to Bottom y = 10x + 65y = 2x - 1y = x + 2y = x - 0.50

julia-pushkina [17]

Answer:

Please see the matches between the equations provided with the data set below.

Step-by-step explanation:

A. y = 10x + 65

It matches with the data set located at the bottom right, where x represents the number of hours studied, and y represents the grade on test.

B. y = 2x - 1

It matches with the data set located at the top right, where we have:

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It matches with the data set located at the bottom left, where:

x y

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D. y = x - 0.50

It matches with the data set located at the top left, where:

x y

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6 0

4 years ago

What is the standard equation for a circle with the center (2,1) and passing through (0, 1)

Volgvan

The radius is the distance from the center to any point. The distance from (2,1) to (0,1) is of course 2. The general formula for a circle with radius r and center (a,b) is

$(x-a)^2 + (y-b)^2 = r^2$

In our case we get

$(x-2)^2 + (y-1)^2 = 4$

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4 years ago

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andre [41]

3.83 I don't really know tho

6 0

3 years ago

Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)

EleoNora [17]

Start by multiplying each side of the inequality by $\sqrt{x + 1}$ and simplifying:

$2 \sqrt x + \frac{1}{\sqrt{x+1}} \leq 2 \sqrt{x + 1}$
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$2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)$
$2 \sqrt{x^2 + x} + 1 \leq 2x + 2$
$2 \sqrt{x^2 + x} \leq 2x + 1$
$\sqrt{x^2 + x} \leq x + \frac{1}{2}$

From here, we can square both sides to get

$x^2 + x \leq (x + \frac{1}{2})^2$
$x^2 + x \leq x^2 + x + \frac{1}{4}$
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3 0

3 years ago

PLEASE WILL MARK BRANLIEST AND IS WORTH 20POINTS!!!!!

svlad2 [7]

Answer:

(3,-2)

Step-by-step explanation:

Part A:

1) Isolate x in x - y = 5

x = y + 5

2) Substitute that x into 4x+y=10

4(y + 5) + y = 10

4y + 20 + y = 10

5y = 10-20

5y = -10

y = -2

3) Use y to solve for x:

x = -2 + 5

x = 3

Part B:

Verify using results from Part A

3 - (-2) = 5

4(3) + (-2) = 12 - 2 = 10

Part C:

Just graph the equations and see where they intersect, which is exactly (3,-2). We got that in Part A and B

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4 years ago