NEED ASAP!!!!
2 answers:
Answer:Triangles BPA and DPC are congruent is used to prove that ABCD is a parallelogram.
Explanation:Here, we have given a quadrilateral ABCD in which diagonals AC and BD bisect each other.
If P is a an intersection point of these diagonals
Then we can say that, AP=PC and BP=PD ( by the property of bisecting)
So, In quadrilateral ABCD,
Let us take two triangles, and
.
Here, AP=PC
BP=PD,
( vertically opposite angles.)
So, By SAS postulate,
Thus AB=CD ( CPCT).
Similarly, we can prove,
Thus, AD=BC (CPCT).
Similarly, we can get the pair of congruent opposite angle for this quadrilateral ABCD.
Therefore, quadrilateral ABCD is a parallelogram.
Note: With help of other options we can not prove quadrilateral ABCD is a parallelogram.
You might be interested in
Notice the picture below
the directrix is above the focus point, meaning the parabola is vertical and is opening downwards
now, "p" is the distance from the vertex to the focus point or the directrix, so that means, the vertex is between those two fellows, over the axis of symmetry, x = -2, since "p" is 1 unit, that puts the vertex at -2,5
since the parabola is opening downwards, that means the "p" value is negative, so is -1
the directrix is above the focus point, meaning the parabola is vertical and is opening downwards
now, "p" is the distance from the vertex to the focus point or the directrix, so that means, the vertex is between those two fellows, over the axis of symmetry, x = -2, since "p" is 1 unit, that puts the vertex at -2,5
since the parabola is opening downwards, that means the "p" value is negative, so is -1