I'm sorry the picture is blurry. Could you post another one.
Answer:
<u>The original three-digit number is 417</u>
Step-by-step explanation:
Let's find out the solution to this problem, this way:
x = the two digits that are not 7
Original number = 10x+7
The value of the shifted number = 700 + x
Difference between the shifted number and the original number = 324
Therefore, we have:
324 = (700 + x) - (10x + 7)
324 = 700 + x - 10x - 7
9x = 693 - 324 (Like terms)
9x = 369
x = 369/9
x = 41
<u>The original three-digit number is 417</u>
√32x^10y^n simplies to 4x^5y^3√2y
Then n = 7 because √y^7 = √(y^6 * y) = y^3√y
So √32x^10y^7 = 4x^5y^3√2y
Answer
n = 7
