Answer:
Step-by-step explanation:
The parent function of this graph is: y = sin(x)
The sine function is periodic, meaning it repeats forever.
Standard form of a sine function:
- A = amplitude (height from the mid-line to the peak)
- 2π/B = period (horizontal distance between consecutive peaks)
- C = phase shift (horizontal shift - positive is to the left)
- D = vertical shift
The parent function y = sin(x) has the following:
- Amplitude (A) = 1
- Period = 2π
- Phase shift (C) = 0
- Vertical shift (D) = 0
- Mid-line: y = 0
From inspection of the given graph:
- Amplitude (A) = 1
- Phase shift (C) = 0
- Vertical shift (D) = +3 (as mid-line is y = 3)
Substituting the values into the standard form:
Therefore, the equation of the given trigonometric graph is:
Answer:
Somewhere between 12 and 13, perhaps 12.25
Step-by-step explanation:
This is a (rather) simple explanation:
Look for 2 square numbers that are either side of 150
In this case, it is 144 and 169
The square root of 144 is 12 and the square root of 169 is 13
Therefore we can estimate that the square root of 150 is somewhere between 12 and 13.
As 150 is a lot closer to 144 to 169, I would estimate around 12.25 but you do not need an exact value :)
Answer: 1, 2, 4, or 5
Step-by-step explanation:
The relationship in #3 is a function because all the x values are distinct, that is, none are repeated. (Y values don't matter.)
A function will not repeat any x values so if your goal is for the relationship in #4 to NOT be a function, repeat one of the x values. Any one will work.
Answer:
3.66meters long
Step-by-step explanation:
since it's 6% shorter you calculate 3.9 times .94(which is basically 94 percent) which gives you 3.66 meters long
Answer:
The angles formed on line b when cut by the transversal are congruent with ∠2 are 
Step-by-step explanation:
Consider the provided information.
If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .
The angles on the same corners are called corresponding angle.
Alternate Angles: Angles that are in opposite positions relative to a transversal intersecting two lines.
∠2 and ∠6 are corresponding angles
Therefore, ∠2 = ∠6
∠2 and ∠7 are alternate exterior angles
Therefore, ∠2 = ∠7
Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are
