To check for continuity at the edges of each piece, you need to consider the limit as
approaches the edges. For example,

has two pieces,
and
, both of which are continuous by themselves on the provided intervals. In order for
to be continuous everywhere, we need to have

By definition of
, we have
, and the limits are


The limits match, so
is continuous.
For the others: Each of the individual pieces of
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
You could factor a 7 out of 7 + 14 to get 7(1 + 2).
This would equal the same thing as 7 + 14, which is 21.
7 * 3 = 21.
21 can be factored like so:
1 * 21 = 21
3 * 7 = 21
Answer:
Yes
Step-by-step explanation:
1 : The athlete's hands push the medicine ball forward. The medicine ball pushes the athlete's hands backward.
2: Friction
3: The first pair of action-reaction force pairs is: foot A pushes ball B to the right; and ball B pushes foot A to the left. The second pair of action-reaction force pairs is: foot C pushes ball B to the left; and ball B pushes foot C to the right
Answer:
The amount of sale is approximately 5714.
Step-by-step explanation:
Let x be the sales made that will result to the same salary and let y be the same weekly salary.
We can represent both salaries as follows:
300 + 0.04x = y
100 + 0.075x = y
Subtracting the second equation from the first, we have:
200 – 0.035x = 0
0.035x= 200
x = 200/0.035
x ≈ 5714.
Therefore, the amount of sale is approximately 5714.
Answer:
The probability that he picked 2 purpled socks is <u>0.33</u>.
Step-by-step explanation:
Given:
Number of purple socks, 
Number of orange socks, 
Two socks are picked without replacement.
Now, total number of socks, 
Probability of picking the first cap as purple cap is given as:

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.
Therefore, probability of picking the second cap as purple cap is given as:

Now, probability that both the picked caps are purple is given by their probability product. This gives,

Therefore, the probability that he picked 2 purpled socks is 0.33