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3 years ago

The arrow on the spinner is to be spun once.

Mathematics

2 answers:

liubo4ka [24]3 years ago

7 0

I think your anwser is D

Sholpan [36]3 years ago

7 0

<span>The arrow on the spinner is to be spun once. The sample space = D. {1, 2, 3, 4, 5, 6};</span>

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A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of

disa [49]

Answer:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48$

For this case this value means that the expected score is about 7.48

Step-by-step explanation:

For this case we assume the following probability distribution:

X 5 6 7 8 9 10

P(X) 0.05 0.15 0.33 0.28 0.12 0.07

First we need to find the expected value (first moment) and the second moment in order to find the variance and then the standard deviation.

In order to calculate the expected value we can use the following formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48$

For this case this value means that the expected score is about 7.48

In order to find the standard deviation we need to find first the second moment, given by :

$E(X^2)=\sum_{i=1}^n X^2_i P(X_i)$

And using the formula we got:

$E(X^2)=(5^2 *0.05)+(6^2 *0.15)+(7^2 *0.33)+(8^2 *0.28)+ (9^2 *0.12 +(10^2 *0.07))=57.46$

Then we can find the variance with the following formula:

$Var(X)=E(X^2)-[E(X)]^2 =57.46-(7.48)^2 =1.5096$

And then the standard deviation would be given by:

$Sd(X)=\sqrt{Var(X)}=\sqrt{1.5096}=1.229$

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4 years ago

Read 2 more answers

John randomly picks a number from 1 to 5 (both inclusive) and a letter from A to E (both inclusive). What is the probability tha

Greeley [361]

Answer:

$P(A \cap B) = P(A) *P(B) =\frac{1}{5} \frac{1}{5}= \frac{1}{25}$

So then the best option would be:

a. 1/25

Step-by-step explanation:

For this case we assume that the sample space for the numbers is :

$S_1= [A,B,C,D,E]$

And the sample space for the numbers is:

$S_2 =[1,2,3,4,5]$

Both sampling spaces with a size of 5.

We define the following events:

A="We select a 2 from the numbers"

B= "We select a E from the letters"

We can find the individual probabilities for each event like this:

$P(A)= \frac{1}{5}$

$P(B) = \frac{1}{5}$

And assuming independence we can find the probability required like this:

$P(A \cap B) = P(A) *P(B) =\frac{1}{5} \frac{1}{5}= \frac{1}{25}$

The last probability is the probability of obtain obtain a 2 AND an E

So then the best option would be:

a. 1/25

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