Answer:
Step-by-step explanation:
The equation of the ellipse is
If the vertex of the ellipse is at point (-7,0), then a=7.
If the co-vertex of the elllipse is at point (0,-5), then b=5.
The equation of the ellipse is
Answer:
The solutions are {-5, 1}
Step-by-step explanation:
Next time, please use the symbol " ^ " to denote exponentiation:
x^2+4x-5=0
Start by identifying the coefficient of the x term (it is 4 here). Divide this by 2, resulting in 2. Square this result (square 2), obtaining 4.
Now add this 4 after the 4x term, and then subtract this 4:
x^2+4x +4 - 4 -5=0
Rewrite x^2+4x + 4 as (x + 2)²:
(x + 2)² - 9 = 0
Add 9 to both sides, to isolate (x + 2):
(x + 2)² = 9
Take the square root of both sides:
x + 2 = ±3
Solve for x: x = -2 + 3, or 1
x = -2 - 3, or -5
The solutions are {-5, 1}
Answer:
Step-by-step explanation:
If the value a is positive in the linear equation y = a x ( for example: y = 2 x ) then the line ( from the left to the right ) must go up and to the right. It also passes through the origin ( 0, 0 ). For x = 1: y = 2 * 1 = 2, so that point is ( 1, 2 ), x2 > x1, and y2 > y1.Answer:A. goes up and to the right.
Answer:
(3,5)
Step-by-step explanation:
Here we are asked to find the reflection of Point P(-1,5) along the line represented by x=1
Please refer to the image attached with answer.
We have point P (-1,5) , the line x=1 and the Point R which is the reflection of P across x=1
now we can see that P is 2 units towards left of the line x=1. hence its reflection across x=1 will be 2 units away towards right of line. 2 units away , the x coordinate will be 1+2 = 3
Hence the x coordinate is 3 and y coordinate remains the same. Hence the coordinates of R will be (3,5)
N the xy-plane above<span>, </span>O is the center<span> of the cirlce. In the </span>xy-plane above<span>, </span>O is the center<span> of the cirlce, and the </span>measure<span> of angle AOB is pie/a radians</span>
