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4 years ago

46.059 and 46.23 which is the faster time

Mathematics

2 answers:

ioda4 years ago

6 0

46.059 since if you put a zero in 46.23 like 46.023 so you can compare them, 46.059 is still greater

snow_lady [41]4 years ago

4 0

46.059 is the faster time because it is a smaller number than 46.23 by 0.171

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Lucy earns 52 dollars each week working part-time at a bookstore. She earns one additional dollar for each book that she sells.

Misha Larkins [42]

Answer:

A = B + 52

Step-by-step explanation:

A is the total amount each week. 52 is the initial amount that she earns each week. Then, B represents the amount of books she sells. So, 15 books can be represented by

A = 15 + 52 = 67

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Kim was walking down a rocky path.For 4 minutes, the elevation dropped steadily.All together it dropped 8 feet. What was the cha

fenix001 [56]

Answer:

2 $\frac {{\textrm{feet}}}{{\textrm{minute}}}$

Step-by-step explanation:

Kim was walking down a rocky path. For 4 minutes, the elevation dropped steadily. All together it dropped 8 feet.

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3 years ago

The reflection of the point (4, 6) over the y-axis is:

Brums [2.3K]

(-4,6)
The x value changes bc since it is a reflection y cannot change and x becomes negative

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3 years ago

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Solve the inequality 3u+3(u+1)>2u+7 and write the solution in interval notation.

strojnjashka [21]

<u>Given</u>:

The given inequality is $3u+3(u+1)>2u+7$

We need to determine the solution of the inequality in interval notation.

<u>Solution of the inequality:</u>

The solution of the inequality can be determined by simplifying the inequality.

Thus, we have,

$3u+3u+3>2u+7$

$6u+3>2u+7$

Subtracting both sides by 3, we get;

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Subtracting both sides by 2u, we have;

$4 u>4$

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3 years ago

What is the solution to the trigonometric inequality 2sin(x)+3>sin ^2(x) over the interval

navik [9.2K]

The intervals that satisfy the given trigonometric Inequality are; 0 ≤ x < 3π/2 and 3π/2 < x ≤ 2π

<h3>How to solve trigonometric inequality?</h3>

We are given the trigonometric Inequality;

2 sin(x) + 3 > sin²(x)

Rearranging gives us;

sin²(x) - 2 sin(x) - 3 < 0

Factorizing this gives us;

(sin(x) - 3)(sin(x) + 1) < 0

Thus;

sin(x) - 3 = 0 or sin(x) + 1 = 0

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sin(x) = 3 is not possible because sin(x) ≤ 1.

Thus, we will work with;

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Then, x = sin⁻¹(-1)

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Now, if we split up the solution domain into two intervals, we have;

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From 3π/2 < x ≤ 2π, take x = 2π. Then;

sin²(2π) - 2 sin(2π) - 3

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Thus, the interval 3π/2 < x ≤ 2π is also true.

Read more about trigonometric inequality at; brainly.com/question/27862380

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