In 4x3=12 12 is called the ???

The function f(x) =2(3)^x is to be multiplied by the function g(x) 3(3)^(2x) to create the function h(x). Which function is prod

maria [59]

Answer C is the right answer.

Step-by-step explanation:

h(x) = f(x) * g(x)

h(x) = (2*3^x ) * ( 3*3^2x )

2 * 3 is easy, that will be 6.

The ground number 3 remains 3 in h(x), so that is easy too...

But with multiplying exponents, you can add them.

Let's concentrate only on the exponents of f(x) and g(x)... and add them...

x + 2x =3x

So, now combine the easy part with this new exponent, and you get h(x) = 6*(3)^(3x)

So answer C is the right answer.

7 0

3 years ago

Will mark brainliest

Lilit [14]

(2x+1)+(3x-5)=5x-4 you just have to try some of them out and see which ones work

5 0

3 years ago

Can you form a right triangle with the three lengths given? Why or why not? 4mi, 5mi, 6mi

Vladimir [108]

A right triangle must satisfy this equation: a^2 + b^2 = c^2

a= shortest length
b=medium length
c=the longest length

a triangle with sides 4,5,6 will satisfy not this equation because:
4^2 + 5^2 ≠ 6^2
16+25 = 41

41 ≠ 36

so the answer is C.

Hope this helps.

-Jabba

6 0

3 years ago

Read 2 more answers

Which statement is always true about the measures of alternate interior angles?

KiRa [710]

N/A

[FAILED CONNECTION]

3 0

3 years ago

Suppose you roll a fair six-sided die. Then you roll a fair eight-sided die. Match each probability to its correct value.

Anna35 [415]

Answer:

A) matches $\frac{5}{48}$

B) matches $\frac{1}{12}$

C) matches $\frac{1}{4}$

D) matches $\frac{1}{8}$

E) matches $\frac{5}{16}$

Step-by-step explanation:

The sample space for the roll of six sided die and eight sided die:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (1,7), (1,8)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (2,7), (2,8)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (3,7), (3,8)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (4,7), (4,8)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (5,7), (5,8)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6), (6,7), (6,8)

Therefore, the total number of outcomes (Sample space) = 48

Probability $=\frac{Number Of Ways Event Can Occur}{Sample Space}$

A) The possible ways of obtaining both numbers are odd numbers and their product is greater than 10 are: (3,5), (3,7), (5,3), (5,5), (5,7)

Total number of possible ways = 5

Sample space = 48

The probability that both numbers are odd numbers and their product is greater than 10:

$=\frac{5}{48}$

B) The possible ways of obtaining second number is twice the first number are: (1,2), (2,4), (3,6), (4,8)

Total number of possible ways = 4

Sample space = 48

The probability that the second number is twice the first number:

$=\frac{4}{48}$ $=\frac{1}{12}$

C) The possible ways of getting numbers whose sum is a multiple of 4 are: (1,3), (1,7), (2,2), (2,6), (3,1), (3,5), (4,4), (4,8), (5,3), (5,7), (6,2), (6,6)

Total number of possible ways = 12

Sample space = 48

The probability of getting numbers whose sum is a multiple of 4:

$=\frac{12}{48}$ $=\frac{1}{4}$

D) The possible ways of getting the sum of the two numbers is greater than 11 are: (4,8), (5,7), (5,8), (6,6), (6,7), (6,8)

Total number of possible ways = 6

Sample space = 48

the probability that the sum of the two numbers is greater than 11:

$=\frac{6}{48}$ $=\frac{1}{8}$

E) The possible ways of getting the second number rolled is less than the first number are: (1,2), (1,3), (1,4), (1,5), (1,6), (2,3), (2,4), (2,5), (2,6), (3,4), (3,5), (3,6), (4,5), (4,6), (5,6)

Total number of possible ways = 15

Sample space = 48

The probability that the second number rolled is less than the first number:

$=\frac{15}{48}$ $=\frac{5}{16}$

5 0

3 years ago