Just draw a graph and plot them on the graph then count how many squares (in short) there is between them.
Range is the y values or ouputs
domain is inputs or x vvalues
we can use any x value
but at a certain y value, w can't go below that
find thatminimum
find the vertex
for
ax^2+bx+c
the x value of the vertex is
-b/2a
plug that in to the equaiton to get the y value
-b/2a=-(-6)/(2*2)=6/4=3/2
plug that in
2(3/2)^2-6(3/2)-9
2(9/4)-9-9
9/2-18
4.5-18
-13.5
domain=all real numbers
range=from -13.5 to positive infinity
Answer:
B
Step-by-step explanation:
Because the expression in b is saying whatever number n is say 9 then your subtracting 4 by N or like I said take 9 for an example which=5
hope it helps
242-94 = 148 (length is 47 more than the width, you double the length to get the perimeter, so you double 47 which equals 94)
148/4 = 37 (4 being the 4 sides of the rectangle)
width = 37
length = 84
Answer:
−40+2n=−4n+8
−40+2n+40=−4n+8+40
2n=−4n+48
2n+4n=−4n+48+4n
6n=48
answer: n=8
Step-by-step explanation:
