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Valentin [98]
3 years ago
5

Simplify (x+3)^2 - 6x

Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0

Answer:

{x}^{2}  + 9

Step-by-step explanation:

{(x + 3)}^{2}  - 6x \\  \\  =  {x}^{2}  +  {3}^{2}  + 2 \times x \times 3 - 6x \\  \\  =  {x}^{2}  + 9  + 6x - 6x \\  \\  =  {x}^{2}  + 9

Tasya [4]3 years ago
5 0

Answer:

The answer is x² + 9.

Step-by-step explanation:

First, you have to get rid of bracket of square :

{(a + b)}^{2}  \: ⇒ \:  {a}^{2}  + 2ab +  {b}^{2}

{(x + 3)}^{2}

= (x + 3)(x + 3)

=  {x}^{2}  + 6x + 9

Next, you can simplify :

{x}^{2}  + 6x + 9 - 6x

= {x}^{2}  + 9

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3 years ago
Which expression is equivalent to (9x10z2)(x5y3)
MAVERICK [17]

Answer:

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Step-by-step explanation:

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3 years ago
Factor the following: x2−16x+64
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Step-by-step explanation:

3 0
3 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
A wise man once said "500 reduced by twice my age is 394." what is his age?
stich3 [128]
X=the man's age
500-2x=394
-500       -500
-2x=-106
-2x/2=-106/-2
x=53

FINAL ANSWER: 53 years old

Hope this helps! :)
5 0
4 years ago
Read 2 more answers
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