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Nataly_w [17]
3 years ago
9

What's 2/3×2/3 please explain

Mathematics
2 answers:
Len [333]3 years ago
7 0
When multiplying fractions you multiply each numerator together and each numerator and denomentaor together
2/3x2/3=4/9
(2*2)/(3*3)=4/9
Luba_88 [7]3 years ago
4 0
Multiply 2 x 2


\frac{2}{3
} (2)
----------------  
         3

Multiply 3 by 3

\frac{4}{3}
__________
        3 

= \frac{4}{9}
You might be interested in
4.44 x 4 = please my sister needs it
Ludmilka [50]

Answer:

17.76

Step-by-step explanation:

0.44 x 4 = 1.76

4 x 4 = 16

16+1.76=17.76

6 0
3 years ago
Write the following as a mathematical expression
andrey2020 [161]
The answer to that problem si 6-25+2x
3 0
3 years ago
Please answer quick!
tatuchka [14]
4 * (25 * 1.2) = (4 * 25) * 1.2
3 0
3 years ago
Read 2 more answers

jekas [21]

Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°

To Find: The length of the park's boundary to the nearest yard.

Calculation:

The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc

or,                    (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)

or,                    (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 209.33 yards

or,                    (P) = 309.33 yards ≈309 yards

Hence, the option D:309 yards is the correct option.

7 0
3 years ago
Read 2 more answers
Law of cosines.Anyone good in Trigonometry?​
marin [14]

Answer:

c=11.8\ units

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

c^2=a^2+b^2-2(a)(b)cos(C)

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

a=3\ units\\b=10\ units

C=120^o

substitute the given values

c^2=3^2+10^2-2(3)(10)cos(120^o)

c^2=109-(60)cos(120^o)

c^2=109-(60)(-0.5))

c^2=109+30

c^2=139

c=11.8\ units

3 0
3 years ago
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