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Leviafan [203]
3 years ago
11

Shakir has relatives in Ottawa, Canada. His aunt told him that the average temperature in April is 8.6°C higher than it is in Ma

rch. She also said that the average temperature in February is −11.8°C.
If the average temperature in April is 3.8°C, how much colder is the average temperature in February than the average temperature in March?

a
It is 7°C colder.
b
It is 4.8°C colder.
c
It is 3.2°C colder.
d
It is 24.2°C colder.

Mathematics
1 answer:
34kurt3 years ago
3 0

Answer:

Step-by-step explanation:

did u get the answer?//

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Please help me on math and explain how to get the answer.
Lynna [10]

Answer:

x = 128

Step-by-step explanation:

ill name the empty angle y for clarification

y + 38 + 90 = 180

y + 128 = 180

y = 52

180 - y = x

180 - 52 = x

x = 128

4 0
3 years ago
Read 2 more answers
10 + 2-x\3 = 7<br><br><br> \ = divided by<br><br> TIA!
Lemur [1.5K]
Your answer to this problem is 15


10 + 2 - 15 / 3 = 7


Hope it helped :)

8 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
Jessica has -$15 dollars in her bank account. Jonathan has less money than Jessica in his bank account. Which value could repres
Radda [10]

Answer:

x∠15 or 15 is greater than x The x being the amount of money Jonathan has in his bank account.

Step-by-step explanation:

Sorry if this is not what you are looking for.

4 0
3 years ago
Please help me do not put random answers
AysviL [449]

Answer:

1) 5x = 25

x = 5

2) y/4 = 7

y = 28

3) n/2 = 19

n = 38

4) 6g = 54

g = 9

5) 8b = 64

b = 8

6) h/6 = 11

h = 66

7) f/4 = 9

f = 36

8) 7s = 49

s = 7

5 0
3 years ago
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