it's plural so axes*
and in pilar coordinates, the axes are circular so they never intersect but the centre point is still called origin.
Answer:
Statements:
m<b = 180 - m<a
m<c = 180 - m<d
m<b = m<c
180 - m<a = 180 - m<d
Reasons:
The measure of m<b is the angle of a straight line subtracted with m<a. The measure of m<c is the angle of a straight line subtracted with m<d. If m<a and m<d are equal, m<b and m<c are equal.
Step-by-step explanation:
We know, m<a = m<d
So, we need to prove m< b = m<c
Let's start by defining what b and c is
m<b + m<a = 180 This is because a straight line is 180 degrees
m<b = 180 - m<a
m<c + m<d = 180
m<c = 180 - m<d
With this, we can substitute in proof
m<b = m< c
180 - m<a = 180 - m<d
180 - m<a = 180 - m<a
Your welcome for the answer. Tell me if you have any questions in the comments section of this answer! If you could mark this answer as the brainliest, I would greatly appreciate it!
Answer:
1 7/8 quarts
Step-by-step explanation:
The amount Yuan has left can be found by multiplying the original amount by the fraction he has left.
__
<h3>used</h3>
After using 1/2 of the broth for soup, the fraction remaining is ...
1 -1/2 = 1/2
The amount Yuan used for gravy is 1/4 of this, or ...
(1/4)(1/2) = 1/8 . . . of the original amount of broth
The total fraction Yuan used was ...
fraction used = fraction for soup + fraction for broth = 1/2 +1/8 = 5/8
<h3>remaining</h3>
Then the fraction remaining is ...
fraction remaining = 1 - fraction used = 1 - 5/8 = 3/8.
The amount remaining is this fraction of the original amount:
(3/8)(5 quarts) = 15/8 quarts = 1 7/8 quarts . . . . remaining
Answer:
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Step-by-step explanation:
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Answer: Hello your question is poorly written attached below is the complete question
answer:
![y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right]](https://tex.z-dn.net/?f=y%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C-11%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
![x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right]](https://tex.z-dn.net/?f=x%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%5C%5C12%5C%5C-40%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
![y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right]](https://tex.z-dn.net/?f=y%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C-11%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
![x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right]](https://tex.z-dn.net/?f=x%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%5C%5C12%5C%5C-40%5Cend%7Barray%7D%5Cright%5D)
attached below is the detailed solution using LU factorization