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blagie [28]
3 years ago
12

I have 3 pennies, 4 nickels, and 5 dimes. What ratio represents the following ratio: nickels to the total number of coins.

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

1:3

Step-by-step explanation:

4:(3+4+5)

4:12

1:3

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In Mr.Kleins class, 40% of the students are boys. What decimal represents the portion of the students that are girls?
Sidana [21]
Percent that are  girls = 100-40  = 60%
As a decimal 60% is 0.6.
4 0
3 years ago
How do you find the intersection of two sets?
Vlad [161]
To find the intersection<span> of these </span>two sets<span>, we need to find out what elements they have in common. The numbers 3, 4, 5 are elements of both </span>sets, therefore theintersections<span> of A and B is {3. 4. 5].</span>
3 0
3 years ago
Michelle multiple 3.4×52. she incorrectly wrote 1,768 as her product.
Lelechka [254]

Answer:

Wrong Answer 176.8

Step-by-step explanation:

Multiply 3.4 * 52 = 176.8


6 0
3 years ago
Read 2 more answers
Kyndal wants to buy a lamp that
fenix001 [56]

Answer:

$39.36

Step-by-step explanation:

Since its 20% off that means we still have a remaining 80% so first multiply 0.8 to the 82

82x0.8= 65.6

Since there is a additional 40% off multiply by 0.4 to get the discount amount

65.6x0.4= 26.24

Subtract the discount from the price

65.6-26.24= 39.36

5 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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