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3 years ago

What fraction in simplest form is equivalent to 0.45

Mathematics

2 answers:

grigory [225]3 years ago

6 0

4/10 tenths 5/100ths or 45/100hundredths

konstantin123 [22]3 years ago

3 0

The simplest from is equivalent to 0.45 is 9/20.

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Divide r+5/r^2+5r-14 by r^2+4r-21/r-2

sergey [27]

r+5 r^2+4r-21
-------------- / --------------------
r^2+5r-14 r-2

 r+5 r-2
= -------------- x --------------------
r^2+5r-14 r^2+4r-21

 r+5 r-2
= -------------- x --------------------
 (r+7)(r-2) (r+7)(r-3)

 r+5
= -----------------
 (r+7)^2 (r-3)

7 0

3 years ago

The model shown represents which of the following?

Pepsi [2]

Answer:

the answer is option four D. -8 + 3

3 0

3 years ago

Suppose that y varies directly with x and y = 10 when x = 20. What is y when x = 15?

tresset_1 [31]

Answer: y = 7.5

Step-by-step explanation:

Suppose that y varies directly with x

That is, y∝x

Convert y∝x to a full equation by introducing a constant k to the right hand side.

Therefore, y = kx

Given that y = 10 and x = 20

Substitute y and x in the equation above. We have;

10 = k(20)

10 = 20k

20k = 10

k = 10/20

k = 0.5

Since k = 0.5, the equation y = kx becomes y = 0.5x

Now, to find y if x = 15, substitute x in equation y = 0.5x

Therefore, y = 0.5(15)

y = 7.5

5 0

3 years ago

Which ordered pairs is a solution to −5x + 3y > 12?

In-s [12.5K]

Answer :-

Given inequality ,

-5x +3y > 12
3y > 5x + 12
y > 5/3x + 12/3
y > 5/3x + 4

From the options ,

When x is 3 and y = 9

y >1* 5 + 4
y > 5 +4
9> 9 ( Not possible )

When x is -5 y is 5

y > 5/3*-5 + 4
y > -8.3 + 4
5 > -3.7 ( Possible )

When x is 3 y is -6

y > 5 + 4
-6 > 9 ( Not possible )

When x is -2 y is -5

y > -3.33 + 4
-5 > -0.67 ( Possible )

When x is 2 y is 8

y > 3.33 + 4
8 > 7.77 ( possible )

When x is -6 y is 0

y > -10 +4
0 > -6 ( possible )

7 0

3 years ago

Read 2 more answers

Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe

solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for $p$ such that $1000p(1-p)$ is maximized. Once we have that $p$ , we can easily find the answer to part b.

Finding the value that maximizes $1000p(1-p)$ is the same as finding the value that maximizes $p(1-p)$ , just on a smaller scale. So, we really want to maximize $p(1-p)$ . To do this, we will do a trick called completing the square.

$p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4$ .

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of $p$ such that the inner part of the square term is equal to $0$ .

$p-1/2=0\\p=1/2$ .

So, the answer to part a is $\boxed{1/2}$ .

We can then plug $1/2$ into the equation for p to find the answer to part b.

$1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250$ .

So, the answer to part b is $\boxed{250}$ .

And we're done!

3 0

2 years ago