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mixer [17]
3 years ago
9

Find the area of each figure. Use 3.14

Mathematics
1 answer:
madreJ [45]3 years ago
7 0
I think its 18.24 because if you multiply it by 3.14 then subtract u should get 18.24
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Need help on these ASAP
Nadusha1986 [10]

Step-by-step explanation:

5: x= 15.3

6: x= 11.7

7: x= 18.6

8:x= 31.7

9: x= 47.0

10:x= 25.0

3 0
3 years ago
Help me solve please
Alex Ar [27]

Answer:

Step-by-step explanation:

The addition of angles ABD and DBC make up the larger angle ABC. We know that angle ABD = 65 and DBC = 60, therefore

angle ABC = 65 + 60 and

angle ABC = 125 degrees

5 0
3 years ago
Mrs. Travis wants to have a clown deliver balloons to her secretary's office. Clowns R Fun charges $ 1.25 per balloon and $ 6 de
choli [55]
Let C be Clowns R Fun charge for b balloons and S be Singing Balloons charge.
C=6+1.25b and S=2+1.95b. C must be less than S.
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6 0
3 years ago
Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.
Blizzard [7]

Answer:

The answer is

y = 3

y =  - 4

Step-by-step explanation:

We must find a solution where

\frac{6}{y + 1}  +  \frac{y}{y - 2}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

\frac{6}{y + 1}  \times  \frac{y - 2}{y - 2}  +  \frac{y}{y - 2}  \times  \frac{y + 1}{y + 1}

Which equals

\frac{6y - 12}{(y -2) (y + 1)}  +  \frac{ {y}^{2} + y }{(y - 2)(y + 1)}

Add the fractions

\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Simplify the right side by multiplying the fraction

\frac{6y}{(y  + 1)(y + 2)}

Set both fractions equal to each other

\frac{6y}{(y + 1)(y - 2)}  =  \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}

Since the denomiator are equal, we must set the numerator equal to each other

6y =  {y}^{2}  + 7y - 12

=  {y}^{2}  + y - 12

(y  + 4)(y - 3)

y =  - 4

y = 3

6 0
3 years ago
Read 2 more answers
Wolfrich lived in Portugal and Brazil for a total period of 14 months in order to learn Portuguese. He learned an average of 130
Ghella [55]
He lived 9 months in Portugal and 5 months in Brazil. This is because 130*9 + 150*5 = 1920.
7 0
3 years ago
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