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kipiarov [429]
3 years ago
14

Which expressions are equivalent to 2(4f+2g)?

Mathematics
1 answer:
zzz [600]3 years ago
4 0
Answers are C) 8f+4g D) 4(2f+g) & E) 4f+4f+4g
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Please help ill mark brainlyst please
kozerog [31]

Answer:

x = 8°

y = 21°

Step-by-step explanation:

27 + 3y = 90

3y = 63

y = 21°

x + 8x + 18 = 90

9x = 72

x = 8°

3 0
3 years ago
One number is 1/2 of another number the sum of the two numbers is 27 find the two numbers
Art [367]
Filling up the space because it has to be 20 characters

4 0
3 years ago
Functions can be defined using graphs, tables, and ordered pairs. Define the domain and range of a function.
Harrizon [31]
The domain is the input and the ramge is the output.

Domain = x Range = y

You cant say that the domain/range is ALL NUMBERS you can only say it is and x/y value.

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3 0
3 years ago
Read 2 more answers
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yanalaym [24]

Your answer would be the first option 10^5.

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6 0
3 years ago
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yanalaym [24]

Answer:

\frac{f(x+h)-f(x)}{h}=2x + h

Step-by-step explanation:

Given

f(x)= x^2 + 2

Required

Determine: \frac{f(x+h)-f(x)}{h}

First, we calculate f(x + h)

f(x)= x^2 + 2

f(x+h) = (x+h)^2+2

f(x+h) = x^2+2xh+h^2+2

So, we have:

\frac{f(x+h)-f(x)}{h} = \frac{x^2 + 2xh + h^2 + 2 - x^2 - 2}{h}

\frac{f(x+h)-f(x)}{h}= \frac{x^2 - x^2+ 2xh + h^2 + 2  - 2}{h}

\frac{f(x+h)-f(x)}{h} = \frac{2xh + h^2}{h}

\frac{f(x+h)-f(x)}{h}=2x + h

8 0
3 years ago
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