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const2013 [10]
3 years ago
8

Which number is greater 20% or 0.02

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
7 0
20% is greater than 0.02 cause (easy way) if you convert 20% to a decimal it'll be .2 (take the 0 off) and .2(0) is greater than 0.02 so the final answer is 20% > 0.02
mylen [45]3 years ago
3 0
To compare these two values, we need them to be in the same form.  

To convert 20% into a decimal, we divide 20/100, or 0.20.  

When comparing decimals, we know that 0.2 > 0.02. 

Therefore, 20% > 0.02.  (20% is greater than 0.02)
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A survey showed that the probability that an employee gets placed in a job that is suitable for the employee is 0.65. A psychome
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Find the volume of the cylinder if the height is 3 mm and the diameter is 40 mm. Leave the answer in terms of it.
KiRa [710]

The Volume of cylinder is 3770 cubic millimeters

But, the correct option is not available in options given.

Step-by-step explanation:

Height of cylinder = 3mm

Diameter of cylinder = 40mm

Volume of cylinder = ?

The formula used to find Volume of cylinder is:

Volume = \pi r^2h

Putting values in the formula:

Since we need radius,

radius = diameter/2

radius = 40/2

radius = 20 mm

So,

Volume = \pi r^2h\\Volume = 3.14*(20)^2*3\\Volume = 3.14*400*3\\Volume= 3769.91 or \,\,\,Volume\approx 3770\,\,cubic\,\,millimeters

The Volume of cylinder is 3770 cubic millimeters

But, the correct option is not available in options given.

Keywords: Volume of cylinder

Learn more about Volume of cylinder at:

  • brainly.com/question/12497249
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  • brainly.com/question/12613605

#learnwithBrainly

6 0
3 years ago
find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}
\\\\\\
d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}
\\\\\\
d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-5&1&5
\end{array}
\\\\\\\
[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
What is the length of the arc when the degree measure is 60° and the radius is 7?
shepuryov [24]
Inscribed angle =1/2 arc
4 0
3 years ago
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