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3 years ago

The table shows the heights of 40 students in a class b.) explain why your answer (a) is an estimate

Mathematics

1 answer:

Damm [24]3 years ago

7 0

Answer:

whatssssssssssssssssssss

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The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the

12345 [234]

Answer:

$4x^2-21x-2$

Step-by-step explanation:

Given that:

Difference of two trinomials is $x^2 - 10x + 2$

One of the two trinomials is $3x^2 - 11x - 4$

To find:

The other trinomial = ?

Four options are:

$2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2$

Solution:

Let the two trinomials be A and B.

Given A - B = $x^2 - 10x + 2$

B = $3x^2 - 11x - 4$

We have to find the other trinomial A.

A - B = $x^2 - 10x + 2$

A - ( $3x^2 - 11x - 4$ ) = $x^2 - 10x + 2$

$\Rightarrow$ A = $x^2 - 10x + 2$ + ( $3x^2 - 11x - 4$ )

$\Rightarrow$ A = $4x^2-21x-2$

So, the correct answer is $4x^2-21x-2$ .

3 0

3 years ago

10 ............... xxsitsktsjgcmgajtajtItjtJfjrzjtskyxmhhdktskyzktzkyxkhdkydktsjtsjtstj

omeli [17]

It’s like -5 or something maybe

7 0

3 years ago

During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be

rusak2 [61]

Answer:

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

$v = \frac{d}{t}$

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that $t = 2.52$ .

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that $v = 3*10^{8}$ m/s.

We have to find d. So:

$v = \frac{d}{t}$

$d = vt$

$d = 3*10^{8}*2.52$

$7.56*10^{8]$

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

7 0

3 years ago

How to determine if a function is even or odd calculus?

aalyn [17]

A function $f(x)$ is even if $f(-x)=f(x)$ , and is odd if $f(-x)=-f(x)$ .

Example:

$f(x)=x^2$ is even, since $f(-x)=(-x)^2=x^2=f(x)$ .

$g(x)=x^3-x$ is odd, since $g(-x)=(-x)^3-(-x)=-x^3+x=-(x^3-x)=-g(x)$ .

6 0

2 years ago

Geometry <br> help please

dexar [7]

The angle m∠UVW can be found using angle of circumference rule in geometry. Therefore, m∠UVW = 67°

<h3 /><h3>Angle on a circumference</h3>

An angle at the circumference of a circle is half the angle at the centre standing on the same arc.

In other words, the angle at the centre of a circle is twice the angle at the circumference.

Therefore,

m∠UVW = 134 / 2

m∠UVW = 67 degrees

learn more on geometry here; brainly.com/question/16836055

#SPJ1

5 0

1 year ago