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sergij07 [2.7K]
3 years ago
12

Which of the following statements is NOT true

Mathematics
2 answers:
slava [35]3 years ago
4 0

Answer :The first one

Step-by-step explanation:

Juliette [100K]3 years ago
3 0
A is the the right one
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the braking distance of a vehicle is directly proportional to the square of its speed. when the speed of the vehicle is b m/s, i
lorasvet [3.4K]
“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.

Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.

Throw 3b into the first equation we have the new d as:
d = k • (3b)^2

Simplifying this, you have d = k•9b or d=9kb

This means the new braking distance is 9 times the original braking distance.
6 0
3 years ago
Which expression has a coefficient of 4?
Maslowich

Answer:

Option D

Step-by-step explanation:

\\ \sf\longmapsto 2(4^x)

  • You have to first find 4^x and then multiply it with two .

Not like this

\\ \sf\longmapsto 2(4^x)=8^x(×)

Hence the variable has coefficient 4 as 4^x is multiplied.

8 0
3 years ago
Please help with this!
dimaraw [331]

Answer:

Expression is 2(l+w)

Step-by-step explanation:

l is length and w is width

5 0
3 years ago
Which measurement is equal to 20 cups? 40 pints 320 fluid ounces 5quarts 1gallon?
Marina CMI [18]
<span>20 Cups = 160 Fluid Ounces
</span><span>20 cup = 10 pint US, liquid
</span><span>20 cup = 5 quart US, liquid</span>
6 0
3 years ago
How to find the average squared distance between the points of the unit disk and the point (1,1)
ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
=\dfrac{\frac{5\pi}2}\pi=\dfrac52
5 0
3 years ago
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